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Ganezh [65]
3 years ago
6

Hellohello, if you able to help me then please do. (:

Mathematics
1 answer:
Alja [10]3 years ago
5 0
The answer is L < 5 .
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The lsrl after an exponential transformation is log yhat=.4785 + 1.468x. What is the exponential form of the regression?
zheka24 [161]

Answer:

10^{0.4785+1.468x}=y

Step-by-step explanation:

So I'm assuming when you typed "log yhat=.4785 + 1.468x", you meant to write: log(y)=0.4785+1.468x. And generally a logarithm can be written in the form log_ba=c which can then be rewritten as b^c=a, but since the log has no base, it's assumed to be 10. So in this case you have the equation:

log_{10}y=0.4785+1.468x, which can then be written in exponential form as:

10^{0.4785+1.468x}=y

8 0
1 year ago
Sketch the curve y=(3x-4)(4x-3)^2
Katyanochek1 [597]
Google has the complete curve of the graph. just search this- <span>y=(3x-4)(4x-3)^2 and it shows. 

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4 0
3 years ago
10n + 7 &gt; n - 3 (5 - 3n)<br><br> plz
Ad libitum [116K]
Are you trying to figure out the value of n?
4 0
3 years ago
Read 2 more answers
If the geometric mean of a and 34 is 6 sqrt(17) find the value of a
Alborosie

Using the geometric mean concept, it is found that the value of a is 18.

----------------------

The geometric mean, of a data-set of n elements, (n_1, n_2, ..., n_n), is given by:

G = \sqrt[n]{n_1 \times n_2 \times ... \times n_n}

That is, the nth root of the multiplication of all elements.

----------------------

In this question:

  • Two elements(n = 2), a and 34.
  • G = 6\sqrt{17}

Thus:

\sqrt{34a} = 6\sqrt{17}

We find the square of each side, so:

(\sqrt{34a})^2 = (6\sqrt{17})^2

34a = 36\times17

Simplifying both sides by 17:

2a = 36

a = \frac{36}{2}

a = 18

The value of a is 18.

A similar example is given at brainly.com/question/15010240

3 0
3 years ago
Which expression is equivalent to (x^-6/x^2)^3<br> 1/x<br> 1/x^5<br> 1/x^9<br> 1/x^24
iVinArrow [24]

Step-by-step explanation:

1/x^24 is the correct expression

4 0
3 years ago
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