The answer is B for apex!
Answer:
61.39%
Explanation:
The percent yield of a substance can be calculated using the formula:
Percent yield = actual yield/theoretical yield × 100%
Based on the information provided on the reaction in this question, the theoretical yield is given as 99.2g while the actual yield is given as 60.9g.
Hence, the percent yield is calculated thus:
% yield = 60.9/99.2 × 100
% yield = 0.6139 × 100
% yield = 61.39%
The percent yield is 61.39%
The volume of O₂ : 21 L
<h3>Further explanation</h3>
Given
8.7 grams of C₂H₄
Required
Volume O₂
Solution
Reaction
C₂H₄ + 3 O₂ ⇒ 2 CO₂ + 2 H₂O
mol C₂H₄(MW= 28 g/mol) :
= mass : MW
= 8.7 g : 28 g/mol
= 0.311
From the equation, mol O₂ :
= 3/1 x mol C₂H₄
= 3/1 x 0.311
= 0.933
At STP, 1 mol gas=22.4 L, so for 0.933 mol :
= 0.933 x 22.4 L
= 20.899 L ≈ 21 L
It’s D because the other ones don’t aren’t true
