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bogdanovich [222]
3 years ago
15

What is the solution to the system of equations graphed below

Mathematics
2 answers:
Crank3 years ago
7 0

Answer:  The correct option is (D) (1, -2).

Step-by-step explanation:  We are given to find the solution to the following system of equations graphed in the picture :

y=-4x+2~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x-3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Comparing equations (i) and (ii), we get

-4x+2=x-3\\\\\Rightarrow 4x+x=2+3\\\\\Rightarrow 5x=5\\\\\Rightarrow x=\dfrac{5}{5}\\\\\Rightarrow x=1.

Substituting the value of x in equation (ii), we get

y=x-3=1-3=-2.

Thus, the required solution of the given system is (x, y) = (1, -2).

Option (D) is CORRECT.

Morgarella [4.7K]3 years ago
3 0
Equation 1 ==> y = -4x + 2
Equation 2 ==> y = x - 3

Substitude equation 2 into 1

x - 3 = -4x + 2
-5 = -5x
x = 1

Substitude x into equation 2

y = 1 - 3
y = -2

Coordinates is (1, -2)
Answer is D.
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Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
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x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

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We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

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x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

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