5. Calculate the acceleration of a 2 kg block across a table if you push with a force of 20 N and the frictional force is 4 N.
1 answer:
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Answer:
α = 1930.2 rad/s²
Explanation:
The angular acceleration can be found by using the third equation of motion:
where,
α = angular acceleration = ?
θ = angular displacement = (1500 rev)(2π rad/1 rev) = 9424.78 rad
ωf = final angular speed = 0 rad/s
ωi = initial angular speed = (960 rev/s)(2π rad/1 rev) = 6031.87 rad/s
Therefore,
<u>α = - 1930.2 rad/s²</u>
<u>negative sign shows deceleration</u>
To solve this problem it is necessary to apply the kinematic equations of motion (vertical in this case) as well as the momentum conservation equations.
For conservation of the moment we have to
Where
Mass of each object
Initial velocity of arrow
= Final Velocity
Time in flight for arrow-apple combination is
Where,
h = Max height
g = Gravitational acceleration
Now after the impact arrow-apple combination have horizontal velocity V and it is
From the previous definition we have that the value of time would be,
Assuming the son's height is 1.85m, then we should
Applying again the conservation equation we can obtain the value of the apple mass as:
Therefore the mass of the apple was 140.7g