5. Calculate the acceleration of a 2 kg block across a table if you push with a force of 20 N and the frictional force is 4 N.
1 answer:
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Answer:
Initial velocity = 39.2m/s
Maximum height is 78.4m
Explanation:
Given
Solving (a): Initial Velocity
Using first law of motion:
Where
<em /><em> [g represents acceleration due to gravity]</em>
Substitute these value in the above formula:
Take g as 9.8m/s²
<em>Hence, initial velocity = 39.2m/s</em>
Solving (b): Maximum Height
This will be solved using second equation of motion
This becomes
Substitute values for u, t and g
<em>Hence, the maximum height is 78.4m</em>