Answer:
<em>Two</em><em> </em><em>sides</em><em> </em><em>and</em><em> </em><em>angle</em><em> </em><em>between</em><em> </em><em>them</em><em> </em><em>is</em><em> </em><em>given</em><em> </em>
Answer:
The Answer is below!!
Explanation:
The larger the area of the parachute, the more air needs to be pushed out of the way, and so the slower it descends. the independent variable is the shape of the parachutes' canopies. The dependent variable is the drop speeds of the parachutes. How long does it take for the parachutes to reach the ground? Measure this using a stopwatch.
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Hi,Find answers from Task 5
1.(X+4)+(X)+(X+4)+(X)=50cm
4x+8=50cm
4x=42
X=10.5cm
Length=10.5+4=14.5cm
Width=10.5cm
Area= length × width=(10.5/100) × (14.5/100) =0.0152m2
2. Volume of a sphere= 4/3 ×π×r³
4/3 ×π×r³=3.2×10^-6 m³
r³=3.2×10^-6 m³/1.33×π
r³=7.64134761e-7
r=0.00914m
Surface area of the blood drop= 4πr²
=4×3.142×0.00914×0.00914=0.00105m²
3.
Equation of an ideal gas = PV =n RT
Equation for pressure, = P= n RT/V
Equation for the volume of an ideal gas= V= n RT/P
If the volume of gas doubles ,V(new)= 2n RT/P
Equation for temperature of an ideal gas, T = PV/n R
If temperature of gas triples, T (new)= 3PV/n R
New Equation for Pressure, = n× R× (3PV/n R)/(2n RT/P)
Pressure factor increase= P(new)/P(old) ={ n× R× (3PV/n R)/(2n RT/P)}/{ n RT/V}
=3PV²/2n RT
