A light beam shines through a slit and illuminates a distant screen. The central bright fringe on the screen is 1.00 cm wide, as
1 answer:
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Answer 1) : 62.5 km/hour is the average velocity of the train.
2) The final velocity of the car at the end of 75 m is 14.69 m/s
Explanation:
1) Displacement of the train = 100 km + 150 km = 250 km
Total time train took =1 hour 15 min+ 45 min + 2 hours = 240 min = 4 hours
Average velocity=
62.5 km/hour is the average velocity of the train.
2) The acceleration of the car, a= 1.2
Distance covered by the car,s = 75 m
Initial velocity of the car , = 6 m/s
Final velocity of thre car ,=?
Using third equation of motion:
The final velocity of the car at the end of 75 m is 14.69 m/s
Answer:
Please refer to the figure.
Explanation:
The crucial point here is to calculate the enclosed current. If the current I is flowing through the whole cross-sectional area of the wire, the current density is
The current density is constant for different parts of the wire. This idea is similar to that of the density of a glass of water is equal to the density of a whole bucket of water.
So,
This enclosed current is now to be used in Ampere’s Law.
Here, represents the circular path of radius r. So we can replace the integral with the circumference of the path,
.
As a result, the magnetic field is
