If the separation distance is doubled, then the electric field decreases by a factor of 4.
<h3>What is the electric field strength?</h3>
We know that the electric field strength is known to depend on the magnitude of the charge and the distance of separation. We know that the electric field refers to the region in which the influence of a charge is felt. Recall that a charge is a specie that is positively or negatively charged. The charge on a specie must always be shown by its sign.
We know that the electric field is the region in space where the influence of a charge can be felt. If a charge is placed in the vicinity of another charge, the second charge would experience a force due to the presence of the first charge. This is because the second charge was brought into the electric field of the first charge.
Thus we know that;
E = Kq/r^2
Where;
E = electric field strength
q = magnitude of charge
r = distance of separation
Now;
E = 9.0* 10^9 * 3.052 * 10^-6/(8.22 * 10^-2)^2
E = 4 N/C
Given that the electric filed strength is inversely proportional to the distance of separation, when the distance between the charges is doubled, the electric field decreases by a factor of 4.
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In option A there are two resistors in which two terminals of resistors are connected with the terminals of battery so here they are connected in parallel.
In option B all resistors and battery is connected in a single loop so it is a series combination of all.
In option C all three resistors are connected by their terminals to a single battery so here all three resistor are in parallel with the battery.
In option D only one resistor is connected in series with a battery as one single loop is there.
So in the above all cases two resistors are in parallel with battery in option A
The answer of speed is 4.5m/s
We know that the electric field is equal to 1 E 6 V/m
The distance between the thundercloud and the ground is 1.6km = 1600m
Electric field = Voltage/distance
This means that the breakdown voltage must be equal to
V = 1 E 6 V/m * 1600m = 1.6 E 9 V = 1.6 GV
