Answer:
The partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C Is 0.103 atm.
The correct option is A.
Explanation;
NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C
NH4I(s)= 0.215
NH3(g)=0.103
HI(g)Kp=0.112
Therefore = 0.103 +0.112= 0.215
Therefore the partial pressure of ammonia at equilibrium is 0.103 atm
Respuesta:
292 g / mol;
Por favor, consulte la explicación.
Explicación:
El número de átomos de cada elemento en el compuesto: Fe2 (co3) 3.
Fe = 2; C = 3; 0 = 3 * 3 = 9
Fe2 = 112 g / mol
C = 12 g / mol
O = 16 g /
Masa molecular = ((112 + (12 * 3) + (16 * 9)
= (112 + 36 + 144)
= 292 g / mol.
Total = 2 + 3 + 9 = 14
Fe2 = 112/292 * 100% = 38,356%
C = 36/292 * 100% = 12,328 * '
O = (16 * 9) / 292 * 100% = 49,32%
Answer:
See Explanation Below
Explanation:
A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.
B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5
C) The rate will increase by 4 since you are doubling both you have to multiply them both.
The answer is motion, this is what I would go with because when you are dealing with gases it puts motion in the term of particles.
