D because wants you add the equation it should increase temp but decrease the value in pressure
Answer:
The solutions are ordered by this way (from lowest to highest freezing point): K₃PO₄ < CaCl₂ < NaI < glucose
Option d, b, a and c
Explanation:
Colligative property: Freezing point depression
The formula is: ΔT = Kf . m . i
ΔT = Freezing T° of pure solvent - Freezing T° of solution
We need to determine the i, which is the numbers of ions dissolved. It is also called the Van't Hoff factor.
Option d, which is glucose is non electrolyte so the i = 1
a. NaI → Na⁺ + I⁻ i =2
b. CaCl₂ → Ca²⁺ + 2Cl⁻ i =3
c. K₃PO₄ → 3K⁺ + PO₄⁻³ i=4
Potassium phosphate will have the lowest freezing point, then we have the calcium chloride, the sodium iodide and at the end, glucose.
<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm
<u>Explanation:</u>
For the given chemical equation:

The expression of
for above reaction follows:

We are given:

Putting values in above equation, we get:

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm
Answer:
i think it will increase the rate of chemical reaction as pressure is directly proportional to the reactivity of gas.