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LiRa [457]
3 years ago
13

Bap-fvjt-fxy aa jao sblet's talk????​

Mathematics
2 answers:
Tasya [4]3 years ago
6 0
Hiii!! Do you need help in any question?
zhannawk [14.2K]3 years ago
3 0

answer: What's up?????

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Please help me with this problem
Arada [10]

Answer:

25

Step-by-step explanation:

9+13+3 = 25

__________

7 0
3 years ago
5x – 2x + 7 – x = ?x + ?
fomenos

Step-by-step explanation:

5x – 2x + 7 – x = ?x + ?

I need the answer for "no solution" and "infinite solutions".

NO SOLUTION:

no solution because any value you give to x is not solvable, it remains +7

5x – 2x + 7 – x = ?x + ?

2x = 2x + 7

INFINITE SOLUTION

infinite solutions because any value you give to x is solvable

5x – 2x + 7 – x = ?x + ?

5x – 2x + 7 – x = 2x + 7

2x + 7 = 2x + 7

8 0
2 years ago
Which of the following statements is true?
vlada-n [284]
The number -4 is a whole number
7 0
3 years ago
Please help, I need help.<br><br>I don't understand.
Lana71 [14]

Find slope of both

#1

  • (11,2)
  • (22,4)

\\ \tt\hookrightarrow m=\dfrac{4-2}{22-11}=\dfrac{2}{11}=1.8

#2

  • (0,0)
  • (5,1)

\\ \tt\hookrightarrow m=\dfrac{1-0}{5-0}=\dfrac{1}{5}=0.2

Option C is correct

7 0
2 years ago
Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro
umka21 [38]

|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%

8 0
3 years ago
Read 2 more answers
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