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3 years ago

Round 19.432 to the nearest whole

Mathematics

2 answers:

andre [41]3 years ago

4 0

The nearest whole number is 20.

nexus9112 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

if the number was 19.5 or later up to 20 then the answer would have been 20

but your number was 19.432 which is less then 19.5 so the your answer is 19.

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Find the perimeter of the window to the nearest hundredth.

Natalka [10]

7.71 feet is your answer.

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2 years ago

On babylonian tablet ybc 4652, a problem is given that translates to this equation: x x plus startfraction x over 7 endfraction

seraphim [82]

The correct option is (A). The solution of the equation is x=48.125.

Given an equation $x+\frac{x}{7}+\frac{1}{11}\left(x+\frac{x}{7}\right)=60$ .

A statement that uses the equal sign to show that two expressions have the same value is called an equation. The equation is represented as ax+by=c.

Firstly, we will apply the distributive property to the given equation a×(b+c)=ab+ac, we get

$x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60$

Now, we will simplify the right-hand side equation by taking LCM, we get

$\begin{aligned}\frac{77x+11x+7x+x}{77}&=60\\ \frac{96x}{77}&=60\end$

Further, we will multiply both sides with 77, we get

77×(96x/77)=77×60

96x=4620

Then, we will divide both sides with 96, we get

96x/96=4620/96

x=48.125

Hence, the solution of the given equation $x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60$ is x=48.125.

Learn more about solution of equation from here brainly.com/question/1477785

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4 0

2 years ago

Jay bought 6 bags of maize at shs 2700 each.He sold the bags at shs.3300 each. what was his profit?

NISA [10]

Answer:

3300-2700= 600 x 6 = 3600

7 0

3 years ago

The Answer is 5/24 that’s it

Paraphin [41]

Yh The answer is 5/24

8 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago