Answer: q = -52.5 μC
Explanation:
The complete question is given thus;
A point charge Q moves on the x-axis in the positive direction with a speed of 280 m/s. A point P is on the y-axis at y=+70mm. The magnetic field produced at the point P, as the charge moves through the origin, is equal to -0.30uTk. What is the charge Q? (uo=4pi x 10^-7 T m/A).
SOLVING:
from the given parameters we can solve this problem.
Given that the
Speed = 280 m/s
y = 70mm
B = -30 * 10⁻⁶T
Using the equation for magnetic field we have;
Β = μqv*r / 4πr²
making q (charge) the subject of formula we have that;
q = B * 4 *πr² / μqv*r
substituting the values gives us
q = (-0.3*10⁻⁶Tk * 4π * 0.07²) / (4π*10⁻⁷ * 280 ) = - [14.7 * 10⁻¹⁰k / 2.8 * 10⁻⁵ k ]
q = -52.5 μC
cheers i hope this helped !!!
Answer: 117.8 nm
Explanation:
Given,
Nonreflective coating refractive index : n = 1.21
Index of refraction: = 1.52
Wave length of light = λ = 570 nm =
Hence, the minimum thickness of the coating that will accomplish= 117.8 nm
Population growth is based on four fundamental factors - Birth rate, death rate, immigration and emigration.
Unless I'm missing something, most of the values you are given seem to be irrelevant.
Based on Newton's law of universal gravitation, F=G(m1m2/r^2) where G is the gravitational constant, m1 and m2 are the 2 masses, and r^2 is the distance separating the centres of the 2 masses.
We can substitute the values in to get F=G((1.31x10^22)*(1.55x10^21)/(1.96x10^7)
=3.53x10^18N
Therefore the magnitude of the gravitational force of attraction that Pluto exerts on Charon (and vice versa) is 3.53x10^18N
Answer:
Explanation:
From the question we are told that:
1st's Length
1st's radius
2nd's Length
2nd's radius
Generally the equation for Resistance R is mathematically given by
Therefore
And
Therefore