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zepelin [54]
3 years ago
6

Un rectangulo tiene area de 15/40 cm cuadrados y sabemos que uno de sus lados mide 5/8 cuanto medira el otro lado

Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Queremos encontrar la medida de un lado de un rectangulo, dado que conocemos la longitud del otro lado y el area del rectangulo.

Veremos que el otro lado del rectangulo mide 3/5 cm

Sabemos que para un rectangulo de largo L y ancho W, el area esta dada por:

A = L*W

En este caso sabemos que el area es igual a (15/40) cm^2.

Y sabemos que uno de sus lados (digamos que es el ancho) mide (5/8) cm.

Entonces podemos reemplazar eso en la ecuación del area:

(15/40) cm^2 = L*(5/8) cm.

Ahora podemos resolver esto para L.

L = (15/40 cm^2)/(5/8 cm) = (15/40 cm^2)*(8/5 cm^-1)

L = 3/5 cm

El otro lado del rectangulo mide 3/5 cm

Sí quieres aprender más, puedes leer:

brainly.com/question/8916743

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Answer:3 to 2

Step-by-step explanation:

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3 years ago
800 hundred 2 hundred standord form
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800 = 8 x 10^2 in standard form
200 = 2 x 10^2 in standard form
7 0
3 years ago
A basketball player makes 8 of 22 shots in game 1, 6 of 15 shots in game 2, and 10 of 23 shots in game 3. what percent of the sh
mel-nik [20]

Answer:

40%

Step-by-step explanation:

To find the percentage in each game, you divide the number of successful shots by the number of total shots. For game 1, this looks like: 8/22 = 0.3636, or 36%.

For game 2, this give us 40%, and for game 3, 43%.

Not sure if the question is asking for a game-by-game answer or a grand total, so we'll do both. To find the total percentage over the course of the games, add all the successful shots (8 + 6 + 10 = 24) and all the attempted shots (22 + 15 + 23 = 60), and divide the same way (24 / 60 = 40%).

3 0
3 years ago
Choose all the functions that give the sequence:
TEA [102]

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Further explanation:

We will put n=1,2,3,4,5 to find which functions give the given sequence

<u>f(n) = 2n − 1</u>

Putting values of n

f(1)=2(1)-1=2-1=1\\f(2)=2(2)-1=4-1=3\\f(3)=2(3)-1=6-1=5

This function doesn't generate the given sequence

<u>f(n) = 2n + 1</u>

Putting values of n

f(1)=2(1)+1=2+1=3\\f(2)=2(2)+1=4+1=5\\f(3)=2(3)+1=6+1=7\\f(4)=2(4)+1=8+1=9\\f(5)=2(5)+1=10+1=11

This function generates the given sequence.

<u>f(n) = 2(n − 1) − 3</u>

Putting values of n

f(1) = 2(1 -1) -3=2(0)-3=0-3=-3\\f(2) = 2(2 -1) -3=2(1)-3=2-3=-1\\f(3) = 2(3-1) -3=2(2)-3=4-3=1

This function doesn't generate the given sequence

<u>f(n) = 2(n − 1) + 3</u>

Putting values of n

f(1) = 2(1 - 1) + 3=2(0)+3=0+3=3\\f(2) = 2(2 - 1) + 3=2(1)+3=2+3=5\\f(3) = 2(3 - 1) + 3=2(2)+3=4+3=7\\f(4) = 2(4 - 1) + 3=2(3)+3=6+3=9

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Keywords: Functions, Sequence

Learn more about functions at:

  • brainly.com/question/3071107
  • brainly.com/question/3126500

#LearnwithBrainly

8 0
3 years ago
10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!
In-s [12.5K]
Remark
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.

y = \int (cos(x) + sin(x) ) \, dx = \int{cos(x) \,dx + \int sin(x) \,dx
y = sin(x)  -  cos(x) + C 
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0  -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1

y = sin(x) - cos(x) - 1  <<<<< Answer

Problem Two
Remember that y =  \int\ { \frac{1}{x} } \, dx = ln(|x|) + C
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C  = 0
3 + C = 0
C = - 3

y = ln(|x|) - 3  <<<< Answer
7 0
3 years ago
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