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zepelin [54]
3 years ago
6

Un rectangulo tiene area de 15/40 cm cuadrados y sabemos que uno de sus lados mide 5/8 cuanto medira el otro lado

Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Queremos encontrar la medida de un lado de un rectangulo, dado que conocemos la longitud del otro lado y el area del rectangulo.

Veremos que el otro lado del rectangulo mide 3/5 cm

Sabemos que para un rectangulo de largo L y ancho W, el area esta dada por:

A = L*W

En este caso sabemos que el area es igual a (15/40) cm^2.

Y sabemos que uno de sus lados (digamos que es el ancho) mide (5/8) cm.

Entonces podemos reemplazar eso en la ecuación del area:

(15/40) cm^2 = L*(5/8) cm.

Ahora podemos resolver esto para L.

L = (15/40 cm^2)/(5/8 cm) = (15/40 cm^2)*(8/5 cm^-1)

L = 3/5 cm

El otro lado del rectangulo mide 3/5 cm

Sí quieres aprender más, puedes leer:

brainly.com/question/8916743

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The sales tax rate in New Mexico is $5.125%.
madreJ [45]

Answer:

<em>The tax is $1.54 and the price after tax is $31.54</em>

Step-by-step explanation:

<u>Percentages</u>

The procedure to add a percentage ratio p to a given quantity q is:

* Calculate the increase as i = p*q/100

* Add the increase to the original quantity to get the final quantity f=q + i

It's given the sales tax rate in New Mexico is p=5.125%. A pair of pants in New Mexico costs q=$30 before tax.

* The increase (tax) is i = (5.125*30)/100 = $1.54

* The price after tax is f = $30 + $1.54 = $31.54

The tax is $1.54 and the price after tax is $31.54

6 0
3 years ago
What is the argument of -5\sqrt{3}+ 5i?
Shtirlitz [24]

Answer:

150 degrees

Step-by-step explanation:

Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.

So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length 5\sqrt{3}. The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.

Let's find the complementary angle.

So the opposite side of the complementary angle is 5.

The adjacent side of the complementary angle is 5\sqrt{3}.

\tan(\theta)=\frac{5}{5\sqrt{3}}

\tan(\theta)=\frac{1}{\sqrt{3}}

\theta=\tan^{-1}(\frac{1}{\sqrt{3}})

\theta=30

So 90-30=60.

The answer therefore 60+90=150.

4 0
3 years ago
Please help......................
Lyrx [107]

Answer:

Y IS EVERYTHING THAT IS LESS THAN -3X

Step-by-step explanation:

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7 0
3 years ago
Amira pulls a 3 pound wagon 4 feet. How much work has she done?
Alex787 [66]

Answer:

12 ft-lbs is your answer

8 0
3 years ago
Read 2 more answers
Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

3 0
3 years ago
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