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uranmaximum [27]
2 years ago
5

Find the x-coordinate of A", where A(1, 1) under the

Mathematics
1 answer:
djyliett [7]2 years ago
8 0

Answer:

I think it's 5,1

Step-by-step explanation:

counter-wise of 1,1 is -1,1 and translating it 5 to the right makes it -1+6, 1 = 5,1

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I run out of time in 20 mins please answer I will mark you as brainliest
Maksim231197 [3]

Answer:

Hi there!

Your answer is:

A) -2

Step-by-step explanation:

f(-8) means to plug in -8 for x!

(-8)/4 =

-8/4 = -2

f(-8) = -2

7 0
3 years ago
Read 2 more answers
A line passes through the point (-6,9) and has a slope of 3/2. Write an equation in slope-intercept form for this line.
BaLLatris [955]

Answer:

y=3/2x+18

Step-by-step explanation:

Hi there!

We are given a point (-6,9) and a slope of 3/2

We want to write the equation of this line in slope-intercept form

Slope-intercept form is written as y=mx+b, where m is the slope and b is the y intercept

Since we already know the slope of the line as 3/2, we can substitute it as m into the equation:

y=3/2x+b

Now let's find  b

Since the equation of the line passes through (-6,9), we can use it to help solve for b

Substitute -6 as x and 9 as y:

9=3/2(-6)+b

Multiply

9=-9+b

Add 9 to both sides

18=b

Substitute 18 as b into the equation.

y=3/2x+18

Hope this helps!

7 0
2 years ago
12 bars of soap for $8.69
Deffense [45]
Wow… how is this a question? .-.
8 0
2 years ago
Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
Convert 12 cups to quarts
Trava [24]

Answer: 3 quarts

using the information 1 cup = 0.25 quarts, we can use dimensional analysis or a conversion factor to find the number of quarts in 12 cups.

start by expressing x as your unknown value being the number of quarts

there are 3 quarts in 12 cups

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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