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2 years ago

I KNOW YALL SEE THIS I NEED HELP GOD WILL GIVE U MANY BLESSING HELP A POOR SOUL OUT THE RECENT QUESTIONSSSSSSSSSSSSS. ://///

Physics

2 answers:

grin007 [14]2 years ago

8 0

Answer:

sure

Explanation:

photoshop1234 [79]2 years ago

4 0

Answer:

Explanation:

will do

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Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 22 N

klemol [59]

We have: A= F.s
So, A = 22 x 16
A= 352J
Só A is correct answer

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3 years ago

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A 14 kg block lifted 5 m has a gravitational potential energy of

harina [27]

Answer:

700 joules

Explanation:

potential energy = m × h × g

( m = mass, h = height, g = acceleration due to gravity )

P.E = 14 × 5 × 10
P.E = 700 J

hence, gravitational potential energy of the object is 700J

i hope it helped.....

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3 years ago

Ken’s community is completely dependent on agriculture for their income. They cultivate and breed domestic species for their foo

Katena32 [7]

This is an agrarian society, taken to its extreme. These societies are largely dependent upon farming and related activities as a way of earning income, and also for using the farmed items as a way of supporting oneself as food and clothing.

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3 years ago

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Ignoring friction, what is the acceleration of a 75.0 kg object which is acted upon by an

natulia [17]

Explanation:

we can use the formula F = ma

hence,

500 = 75a

a = 6.666 m/s² or 6(2/3) m/s²

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3 0

2 years ago

A police officer in hot pursuit of a criminal drives her car through an unbanked circular (horizontal) turn of radius 300 m at a

Mamont248 [21]

Answer:

The angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.

Explanation:

Given:

Mass of the driver is, $m=55\ kg$

Radius of circular turn is, $R=300\ m$

Linear speed of the car is, $v=22.2\ m/s$

Since, the car makes a circular turn, the driver experiences a centripetal force radially inward towards the center of the circular turn. Also, the driver experiences a downward force due to her weight. Therefore, two forces act on the driver which are at right angles to each other.

The forces are:

1. Weight = $mg=55\times 9.8=539\ N$

2. Centripetal force, 'F', which is given as:

$F=\frac{mv^2}{R}\\F=\frac{55\times (22.2)^2}{300}\\\\F=\frac{55\times 492.84}{300}\\\\F=\frac{27106.2}{300}=90.354\ N$

Now, the angle of the net force acting on the driver with respect to the vertical is given by the tan ratio of the centripetal force (Horizontal force) and the weight (Vertical force) and is shown in the triangle below. Thus,

$\tan \theta=\frac{90.354}{539}\\\tan \theta=0.1676\\\theta=\tan^{-1}(0.1676)=9.52\approx 10$ °

Therefore, the angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.

3 0

3 years ago