1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MA_775_DIABLO [31]
4 years ago
14

A diamond is cut such that the angle between its top surface and its bottom surface is α. For α=45∘, find the largest possible v

alue of the incident angle θa such that the blue light is totally internally reflected off the bottom surface. Express your answer in degrees to four significant figures.
Physics
1 answer:
Reil [10]4 years ago
4 0

Answer:

i = 61 degree

Explanation:

Given,

\alpha =45^{o}

Now, by the snell's law

sin\theta_c=\frac{1}{n}\\sin\theta_c=\frac{1}{2.450}\\\theta_c=24.09^o

Now,

Sin i / sin r = n 2 / n 1

sin i / sin r (45 - 24.09) = 2.45 / 1

i = 60.97 degree

You might be interested in
An object is located 10.0 cm from a convex mirror. The magnitude of the
Sunny_sXe [5.5K]

Answer:

B. 6.00 cm

Explanation:

6 0
3 years ago
PLEASE HELP!!!
crimeas [40]

Answer: potential to kinetic/mechanical

Explanation:

5 0
3 years ago
A two slit pattern is viewed on a screen 1.00m from the slits if the two third-order minima are 22.0 cm apart what is the width
Bingel [31]

Answer:

4.4 cm

Explanation:

Given:

Distance of the screen from the slit, D = 1 m

Distance between two third order interference minimas, x = 22 cm

Let's say, minima occurs at:

x_n = (n + \frac{1}{2}) \frac{wL}{d}

We have:

2x_2 = 2(2 + \frac{1}{2}) * \frac{w*22}{d}

Calculating further for the width of the central bright fringe, we have:

\frac{w}{d} = \frac{22}{5}

= 4.4 cm

Note: w in representswavelength

8 0
3 years ago
A catamaran with a mass of 5.44×10^3 kg is moving at 12 knots. How much work is required to increase the speed to 16 knots? (One
Andre45 [30]

The work that is required to increase the speed to 16 knots is 14,176.47 Joules

If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;

5.44×10^3 kg = 12 knots

For an increased speed to 16knots, we will have:

x = 16knots

Divide both expressions

\frac{5.44 \times 10^3}{x} = \frac{12}{16}\\12x = 16 \times 5.44 \times 10^3\\x = 7.23\times 10^3kg\\

To get the required work done, we will divide the mass by the speed of one knot to have:

w=\frac{7230}{0.51}\\w= 14,176.47Joules

Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules

Learn more here: brainly.com/question/25573786

8 0
3 years ago
A sphere has a radius of 3.9cm and a density of 7.58 g/cm cubed. What is the mass?
snow_lady [41]

Answer:

m=ρV

V=4/3 * pi * r3

V=1.3 * 3.14 * 3.9^3

V=242.14 cm^3

m=7.58 * 242.14

m=1.8 kG

Explanation:

1. We calculate volume for sphere.

2. Then we calculate mass of sphere.

3 0
3 years ago
Other questions:
  • Volume is the space occupied by a quantity of matter. <br> a.true <br> b.false
    6·2 answers
  • A 2.0-kg object is lifted vertically through 3.00 m by a 150-N force. How much work is done on the object by gravity during this
    9·2 answers
  • Pls help me guys simple question​
    6·1 answer
  • A horse ran 5.75m/s for 3.5min, how far did it travel
    12·1 answer
  • When you kick a ball by a force of 26.3 newtons, what is the magnitude and direction of the force that you experience?
    14·1 answer
  • What is the variable that is manipulated by the experimenter during an experiment called
    14·1 answer
  • What are the two sources of energy for the earth system
    9·2 answers
  • The parallel plates in a capacitor, with a plate area of 9.50 cm2 and an air-filled separation of 3.40 mm, are charged by a 7.60
    12·2 answers
  • What is the behavior that takes place when two waves of equal amplitude collide abd sum up to a bigger wave.
    6·1 answer
  • If a 5 kg bowling ball is lifted to a height of 2 meters, how much potential
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!