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ozzi
1 year ago
13

Tuesday

Physics
1 answer:
irinina [24]1 year ago
3 0

If a teacher had 48 red pens and the ratio of red to blue pens she owns is 6:1, she will have a total of 56 pens

Let the number of red pens be R and the number of blue pens be B.

R = 48

R / B = 6 / 1

48 / B = 6 / 1

B = 48 / 6

B = 8

Total number of pens = Number of red pens + Number of blue pens

Total number of pens = R + B

Total number of pens = 48 + 8

Total number of pens = 56 pens

Therefore, she has a total of 56 pens

To know more about ratio

brainly.com/question/361700

#SPJ9

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A car traveling at 26 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds. What is its acceleration?
saul85 [17]
Alright let's start this off with our basic equation!

Accerlation (a) = ?

Initial velocity (V1)= 26 m/s
Final velocity (V2) = 0 ft/s because the car comes to a complete stop!

Time (t) = 6 seconds

The equation for acceleration is below!
a = \frac{Final velocity - Initial Velocity}{time}

So now, just plug in the values! 
a = \frac{0 - 26}{6}
a = \frac{-26}{6}
a = -4.33 m/s²

Therefore, your acceleration is -4.33 m/s²!! Hope this helped and was one of the branliest answers :') 

5 0
3 years ago
A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of
Neko [114]
The answer is letter C. <span>A train travels from the bottom of a hill to the top of a hill, its moves slower by the time it reaches the top is an example of negative acceleration.

In physics, acceleration can be described as an objects change of velocity. When an object gains velocity, it is positive acceleration, and negative acceleration for the opposite.

</span>

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5 0
3 years ago
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Discuss five occasions when people dance ​
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Answer:

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A spring with spring constant 450 N/m is stretched by 12 cm. What distance is required to double the amount of potential energy
snow_lady [41]

Answer:

<em> The distance required = 16.97 cm</em>

Explanation:

Hook's Law

From Hook's law, the potential energy stored in a stretched spring

E = 1/2ke² ......................... Equation 1

making e the subject of the equation,

e = √(2E/k)........................ Equation 2

Where E = potential Energy of the stretched spring, k = elastic constant of the spring, e = extension.

Given: k = 450 N/m, e = 12 cm = 0.12 m.

E = 1/2(450)(0.12)²

E = 225(0.12)²

E = 3.24 J.

When the potential energy is doubled,

I.e E = 2×3.24

E = 6.48 J.

Substituting into equation 2,

e = √(2×6.48/450)

e = √0.0288

e = 0.1697 m

<em>e = 16.97 cm</em>

<em>Thus the distance required = 16.97 cm</em>

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3 years ago
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