the answer is the speed of blue ball after collision is 2.6v
The R1, R2, R3, R5 and R6 contains current and R4, R7, R8 and R9 do not contain current. Since R8 loop voltages sources cancel VR8 + V – V = 0 so VR8 = 0. The top of R9 potential from ground is +V + V + V – V - V = V. The bottom of R9 potentials from ground is V so VR9 = 0. The left of R7 potential from ground is +V + V – V = V. The right side of R7 potential from ground is +V + V +V – V – V = V. Therefore, VR7 = 0. From the ground the left side of R4 = +V and from the ground the right side or R4 is at V so VR4 = 0. Since we know that R1 must have 2V across it and we know that R6 and R3 each have V/2, R2 has V across it and R5 must have V across it because the potential of its left end from the ground = +V + V = 2V but the potential of its right end from the ground must be +V + V + V – V – V = V.
The percentage of energy available to each organism is always 10 percent .
Q in = Q out
mcΔt in = mcΔt out (c = equal)
mΔt in = mΔt out
200 x (75-25) = M x (25-5)
M = 500 g