Answer:
You can look it up
Explanation: if you don't know what it is look it up on .
Answer:
No
Explanation:
51 / 100 = 510 / 1000
Chance of getting a head is 1 / 2 of total throws
= 1 / 2 × 1000
= 500 is the probability
and the number of heads was just 10 more the the probability...if the was a greater gap, there would be evidence to say the coin is unfair
Answer:
V = 6.33 m/s
Explanation:
Given:
- The length of the wire L = 0.02 m
- The diameter of the wire D = 0.0005 m
- The calibration expression V = 0.0000625*h^2
- Environment temperature T_inf = 298 K
- Surface temperature T_s = 348 K
- The voltage drop dV = 5 V
- The electric current I = 0.1 A
Find:
- the velocity of Air
Solution:
- Calculate the surface area of the wire:
A = pi*D*L
A = pi*(0.0005)*(0.02) = 0.00003142 m^2
- The rate of energy in the wire P:
P = I*dV = 0.1*5 = 0.5 W
- Apply Newton's Law of Cooling:
P = h*A*(T_s - T_inf)
h = P /A*(T_s - T_inf)
Plug in the values:
h= 0.5/ 0.00003142*(348 - 298)
h = 318.27 W /m^2K
- Using the calibration relationship given, compute the velocity of air:
V = 6.25*10^-5 * h^2
V = 6.25*10^-5 * (318.27)^2
V = 6.33 m/s
Answer:
a) Selection and control of material
b) Control of stress
c) Control of the environment
Explanation:
The measures that can be taken to control and prevent the formation of strss corrosion cracks are:
a) Selection and control of material
It deals with the selection of the best quality material that can resist the stress corrosion cracks to a high extent.
b) Control of stress
It is to control or reduce the intensity of the major stress that causes the stress corrosion cracks.
c) Control of the environment
It includes the prevention of the material from the corrosive environment by removing the component from the region or controlling the environment condition around the object.