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Naddik [55]
3 years ago
12

Air is compressed steadily from 100kPa and 20oC to 1MPa by an adiabatic compressor. If the mass flow rate of the air is 1kg/s an

d the compressor efficiency is 80%, determine a) the temperature of air at the exit and b) the required power input of the compressor.
Engineering
1 answer:
igomit [66]3 years ago
6 0

Answer:

(a). 575 kJ/kg.

(b). 290kw.

Explanation:

We have the following set of information or parameters from the question above;

Pressure(1) = 100kPa, Pressure (2) = 1MPa, temperature(1) = b1= 12°C = 285K = 285kJ/kg, efficiency = 80% and the mass flow rate of the air = 1kg/s.

At a temperature of 12°C, we have the value from steam table; gx= 1.2, thus gx22 = 1.2 × (1000/100) = 12.

We have that the value for b12 = 517.

Therefore, the value for h2a can be calculated as;

80/100 = (517 - 285)/ (tp at exist) - 285.

0.8 = 232/ (tp at exist) - 285.

232 = 0.8 × (tp at exist) - 285).

232 = 0.8 (tp at exist) - 228 .

(tp at exist) = 575.

Therefore, the temperature 575 kJ/kg.

Thus, the required power input of the compressor = 1kg/s × ( 575 - 285) = 290kw.

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Answer:

119.35 mm

Explanation:

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Biologists use a sequence of letters A, C, T, and G to model a genome. A gene isa substring of a genome that starts after a trip
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Answer:

You did not mention the programming language for implementation so i am writing a JAVA code.

import java.util.Scanner; // to get input from user

public class Genome{

public static void main(String[] args) { //start of main() function body

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gene stores substring of genome string from startGene to the position i

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Explanation:

This program first asks user to enter a genome string.

The loop starts from the first character of the entered string and this loop continues to execute until the value of i is 2 less than the genome input string length.

triplet variable stores first 3 characters of the genome string in first iteration and then moves through the string taking 3 characters each. This is done by dividing genome string to substring of 3 characters.

If condition checks if the 3 characters of genome string matches ATG using equals() function. If it is true this means start of genome is reached and these triplets are stored in startGene.

Else condition checks the end of the genome as the genome ends before one of TAG, TAA or TGA triplets. So this is checked here.

gene variable holds the triplet value stored in startGene and the value stored in index position i which means it holds the start of the genome till the end of the genome sequence. The end which is pointed by i variable is 2 less than the genome length and it is stored in gene variable.

After the loop ends the substring stored in gene variable is checked for a valid genome sequence by mod operator. If the length of the value stored in gene variable mod 0 is equal to 0 this means genome sequence is found and this string sequence stored in gene is displayed else the no gene is found message is displayed on output screen.

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