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Maslowich
4 years ago
8

The coordinates of point P on a coordinate grid are (−5, −6). Point P is reflected across the y-axis to obtain point Q and acros

s the x-axis to obtain point R. What are the coordinates of points Q and R?
Mathematics
1 answer:
Scilla [17]4 years ago
5 0
Reflection of point (x ,y) about x axis is given by (x,-y) and about y axis is given by (-x,y) .treat the line as plane mirror about which you have to find out point reflection .thus Q is (5 ,-6) and R is(-5,6)..
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Please help!! This is urgent.
skad [1K]

Answers:

Upper Limit = 2.55 cc

Lower Limit = 2.25 cc

cc stands for "cubic centimeters".

==========================================

Explanation:

The tolerance tells us how much we can go over or under our target. It's our margin of error. We add and subtract the tolerance (0.15) from the target we're trying to aim for (2.4)

So the lowest dosage allowed is 2.4-0.15 = 2.25 cc

The highest dosage allowed is 2.4+0.15 = 2.55 cc

The upper limit is 2.55 cc while the lower limit is 2.25 cc

On a number line, we would find that 2.4 is at the midpoint of 2.25 and 2.55; so its at the center of those lower and upper bounds. The distance from the center to each endpoint is the same. That distance would be the tolerance 0.15

3 0
3 years ago
Find lim h->0 f(9+h)-f(9)/h if f(x)=x^4 a. 23 b. -2916 c. 2916 d. 2925
Svetach [21]

\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = \lim_{h\to0}\frac{(9+h)^4-9^4}h

Carry out the binomial expansion in the numerator:

(9+h)^4 = 9^4+4\times9^3h+6\times9^2h^2+4\times9h^3+h^4

Then the 9⁴ terms cancel each other, so in the limit we have

\displaystyle \lim_{h\to0}\frac{4\times9^3h+6\times9^2h^2+4\times9h^3+h^4}h

Since <em>h</em> is approaching 0, that means <em>h</em> ≠ 0, so we can cancel the common factor of <em>h</em> in both numerator and denominator:

\displaystyle \lim_{h\to0}(4\times9^3+6\times9^2h+4\times9h^2+h^3)

Then when <em>h</em> converges to 0, each remaining term containing <em>h</em> goes to 0, leaving you with

\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = 4\times9^3 = \boxed{2916}

or choice C.

Alternatively, you can recognize the given limit as the derivative of <em>f(x)</em> at <em>x</em> = 9:

f'(x) = \displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h \implies f'(9) = \lim_{h\to0}\frac{f(9+h)-f(9)}h

We have <em>f(x)</em> = <em>x</em> ⁴, so <em>f '(x)</em> = 4<em>x</em> ³, and evaluating this at <em>x</em> = 9 gives the same result, 2916.

8 0
3 years ago
A milk container's capacity is one gallon. How many cups would be equal?
kati45 [8]
1 gallon of milk would be 16 cups :) 
4 0
3 years ago
Read 2 more answers
Q 1.) Expand using identities:<br>i. (a+2b)²<br>ii. (5x-3y)²<br>iii. (3a+4)(3a-4)(9a²+16)<br>​
Ganezh [65]

Step-by-step explanation:

#1.

(a + 2b)²

<em>Using identity (x + y)² = x² + 2xy + y², we get:</em>

= (a)² + (2b)² + 2 × (a) × (2b)

= a² + 4b² + 4ab

= a² + 4ab + 4b² Ans.

#2.

(5x - 3y)²

<em>Using identity (a - b)² = a² - 2ab + b², we get:</em>

= (5x)² + (3y)² - 2 × (5x) × (3y)

= 25x² + 9y² - 30xy

= 25x² - 30xy + 9y² Ans.

#3.

(3a + 4)(3a - 4)(9a² + 16)

<em>Using identity (x + y)(x - y) = x² - y², we get:</em>

= [(3a)² - (4)²][9a² + 16]

= (9a² - 16)(9a² + 16)

= (9a²)² - (16)²

= 81a⁴ - 256 Ans.

4 0
3 years ago
What is the product of -3 1/4 and -1 1/2
allochka39001 [22]

Answer:

4 and 7/8

Step-by-step explanation:

4 0
4 years ago
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