Answer:
2/3<9/10; I used 3/4 as a benchmark.
Step-by-step explanation:
2/3<1/2; I used 1/2 as a benchmark.
2/3 = 0.(20/3) = 0.667
1/2 = 0.(10/2) = 0.5
So this is wrong, as 0.667 > 0.5.
1/2=3/5; I used 1/4 as a benchmark.
1/2 = 0.(10/2) = 0.5
3/5 = 0.(30/5) = 0.6
0.5 != 0.6, so this is wrong.
2/3<9/10; I used 3/4 as a benchmark.
2/3 = 0.(20/3) = 0.667
9/10 = 0.(90/10) = 0.9
So this is correct, as 0.667 < 0.9
3/4<2/3; I used 1/2 as a benchmark.
3/4 = 0.(30/4) = 0.75
2/3 = 0.(20/3) = 0.667
0.75 > 0.667, so this is wrong.
Let M=macaws lifespan and D=dogs lifespan
M=5D
70=5D
If you want to know the dogs average lifespan then solve for D which is 14years.
True, regarding the function is (–6, 10) f(–6) = 10
Answer:
-3y - 51
Step-by-step explanation:
combine like terms.
that should be right, or do you have any more info to the question?