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Margaret [11]
3 years ago
7

!!! , ? ? ? (no silly answers please).

Physics
2 answers:
Anna11 [10]3 years ago
6 0

Answer:

hellooo

Explanation:

i think ummm

. . .

Strike441 [17]3 years ago
4 0
…,,,???!!! I am confused. What?
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Two types of positions are
bearhunter [10]

Answer:

Permanent or temporary just took the test

Explanation:

8 0
3 years ago
What must be the charge of a particle having E = 81 N/C at 49 mm from the said particle? Express in Coulombs. Use k = 9.0 x 109 
irina [24]

\text{Given that,}\\\\\text{Electric field strength,}~ E  = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} =   \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle  is}~2.1609\times 10^{-11} ~C

7 0
2 years ago
A 19.0-kg cart is moving with a velocity of 7.20 m/s down a level hallway. A constant force of -13.0 N acts on the cart and its
gulaghasi [49]

Answer:

a. -369.36J

b. -123.9J

c. 9.52m

Explanation:

From the expression for kinetic energy

K. E=1/2mv^2

Since the mass is constant, but the velocity changes. Hence the change in kinetic energy is

K.E=1/2*19(3.6²-7.2²)

K.E= -369.36J

b. to determine the workdone by the force,we determine the distance moved.

But the acceleration is from

F=ma ,

a=f/m

a=-13/19

0.68m/s²

the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

Hence the work done is

W=force * distance

W=-13*9.52

W=-123.9J

d. the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

4 0
3 years ago
Read 2 more answers
Please answer someone!!
Naily [24]

Answer:

10m

Explanation:

3 0
3 years ago
calculate the energy dissipated by an electric iron which draws a current of 5A from a240v power supply for 25minutes​
Sav [38]

Explanation:

Given,

I = 5 A

V = 240 V

T = 25 mins = 1500 sec

Now,

Energy dissipated = IVT= 5×240×1500 = 1800000 J

4 0
3 years ago
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