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Katyanochek1 [597]
3 years ago
7

If there is a solar eclipse, we see a shadow because the sunlight is _______________.

Physics
2 answers:
bulgar [2K]3 years ago
6 0
Refracted. Sunlight is refracted around the moon to produce light on earth during an eclipse.
lesantik [10]3 years ago
4 0

Answer:

reflected by moon

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5 0
4 years ago
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The Pasig Revolving Tower has an estimated height of 45.23 meters. How high is it in yard? ​
hichkok12 [17]

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50.26

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6 0
3 years ago
A) If the mass of the car is doubled (by adding passengers and cargo) by what factor must the
Nostrana [21]

Let Mass be m

  • F=ma

If its doubled then

\\ \sf\longmapsto F=2ma

Hence force also needs to be doubled.

5 0
3 years ago
An AC adapter for a telephone-answering unit uses a transformer to reduce the line voltage of 120 V (rms) to a voltage of 9.0 V.
Illusion [34]

Answer:

1. The number of turns on the secondary output is 18

2. The root mean square power delivered to the transformer is 48 Watts.

Explanation:

A transformer is an electronic device that can be used for increasing or decreasing the value of a given voltage. It consists of primary coils and secondary coil of a definte number of turns. When voltage flows in the primary coil, it induces voltage in the secondary coil. The two types are: step-up and step down transformers.

1. For a given transformer,

          \frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }

where V_{s} is the value of the induced voltage in the secondary coil, V_{p} is he voltage in the primary coil, and N_{s} is the number of turns of the secondary coil, N_{p} is the number of turns in the primary coil.

From the question,

V_{s}  = 9.0 V, V_{p} = 120 V, N_{p} = 240, N_{s} = ?

So that,

           N_{s} = \frac{V_{s}*N_{p}  }{V_{p} }

                = \frac{9 * 240}{120}

               = 18

The number of turns on the secondary output is 18.

2. Power_{rms} = I_{rms} × V_{rms}

                    = 0.4 × 120

                   = 48 W

The rms power delivered to the transformer is 48 Watts.

8 0
3 years ago
If you push twice as hard against a stationary brick wall, the amount of work you do
Alecsey [184]

Answer:

Zero

Explanation:

The work done on an object is given by:

W=Fd cos \theta

where

F is the force applied on the object

d is the displacement of the object

\theta is the angle between the direction of the force and the displacement

In this problem, you are pushing again a stationary wall: this means that the walls does not move. As a result, the displacement is zero: d=0. Therefore, the work done is also zero: W=0.

8 0
3 years ago
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