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Katyanochek1 [597]
3 years ago
7

If there is a solar eclipse, we see a shadow because the sunlight is _______________.

Physics
2 answers:
bulgar [2K]3 years ago
6 0
Refracted. Sunlight is refracted around the moon to produce light on earth during an eclipse.
lesantik [10]3 years ago
4 0

Answer:

reflected by moon

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Why do electrons transfer charge and not protons?
mel-nik [20]
<h2>Answer:Protons interact in ways that electrons do not. ... Electrons are not affected by the strong force, and so they only get trapped by the electrical attraction to the nucleus which is much weaker in ionized atoms.</h2><h2 /><h2>Explanation:Therefore it is easier for electrons to move away from one atom to another, transferring charge.</h2>

3 0
4 years ago
A 60-W, 120-V light bulb and a 200-W, 120-V light bulb are connected in series across a 240-V line. Assume that the resistance o
gulaghasi [49]

A. 0.77 A

Using the relationship:

P=\frac{V^2}{R}

where P is the power, V is the voltage, and R the resistance, we can find the resistance of each bulb.

For the first light bulb, P = 60 W and V = 120 V, so the resistance is

R_1=\frac{V^2}{P}=\frac{(120 V)^2}{60 W}=240 \Omega

For the second light bulb, P = 200 W and V = 120 V, so the resistance is

R_1=\frac{V^2}{P}=\frac{(120 V)^2}{200 W}=72 \Omega

The two light bulbs are connected in series, so their equivalent resistance is

R=R_1 + R_2 = 240 \Omega + 72 \Omega =312 \Omega

The two light bulbs are connected to a voltage of

V  = 240 V

So we can find the current through the two bulbs by using Ohm's law:

I=\frac{V}{R}=\frac{240 V}{312 \Omega}=0.77 A

B. 142.3 W

The power dissipated in the first bulb is given by:

P_1=I^2 R_1

where

I = 0.77 A is the current

R_1 = 240 \Omega is the resistance of the bulb

Substituting numbers, we get

P_1 = (0.77 A)^2 (240 \Omega)=142.3 W

C. 42.7 W

The power dissipated in the second bulb is given by:

P_2=I^2 R_2

where

I = 0.77 A is the current

R_2 = 72 \Omega is the resistance of the bulb

Substituting numbers, we get

P_2 = (0.77 A)^2 (72 \Omega)=42.7 W

D. The 60-W bulb burns out very quickly

The power dissipated by the resistance of each light bulb is equal to:

P=\frac{E}{t}

where

E is the amount of energy dissipated

t is the time interval

From part B and C we see that the 60 W bulb dissipates more power (142.3 W) than the 200-W bulb (42.7 W). This means that the first bulb dissipates energy faster than the second bulb, so it also burns out faster.

7 0
3 years ago
Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows.
kipiarov [429]

<em>Answer:</em>

<em>Melting</em>

<em>Explanation:</em>

<em>I took the quiz and got it right so I am 100 percent sure the answer is, A.melting :)</em>

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3 years ago
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Ear wax, which is produced in the external auditory canal, contains chemicals that guard the ear from infections. TRUE OR FALSE
kobusy [5.1K]
The answer is true not false if the ear gets infection it makes more wax so the infection will clear out of the ear 
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djverab [1.8K]

Explanation:

hdhhrhhrhehhshsujwuuwuwuwwh

6 0
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