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3 years ago

Two types of positions are

Physics

1 answer:

bearhunter [10]3 years ago

8 0

Answer:

Permanent or temporary just took the test

Explanation:

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A 242-g block is pressed against a spring of force constant 1.62 kN/m until the block compresses the spring 10.0 cm. The spring

hammer [34]

Answer:

a) = 3.94 m

b) = 3.15 m

Explanation:

Given

Mass of the block, m = 242 g

Force constant, k = 1.62 kN/m

Compression of the spring, x = 10 cm

Angle of inclination = 60°

a) if we equate the energy at the bottom of the ramp to the energy at a distance d up the ramp, we have

1/2kx² = mgh where, h = dsinΦ

1/2kx² = mgdsinΦ

1/2 * 1.62*10^3 * 0.1² = 0.242 * 9.8 * dsin 60

1/2 * 16.2 = 2.3716 * d sin 60

d sin 60 = 8.1 / 2.3716

0.866 d = 3.415

d = 3.415 / 0.866

d = 3.94 m

b) net force on the block = mgd sin 60 + µ mgd cos 60

8.1 = d[mg sin 60 + µ mg cos 60]

8.1 = d [0.242 * 9.8 * 0.866 + 0.44 * 0.242 * 9.8 * 0.5]

8.1 = d (2.05 + 0.52)

8.1 = 2.57 d

d = 8.1 / 2.57

d = 3.15 m

3 0

3 years ago

Read 2 more answers

1 hr 16 minutes equal how many minutes ?

Len [333]

Answer:

76 minutes.

Explanation:

There are 60 minutes in an hour + 16 minutes= 76 minutes.

4 0

3 years ago

Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied

Karolina [17]

Ans:

12500 N/C

Explanation:

Side of square, a = 2.42 m

q = 4.25 x 10^-6 C

The formula for the electric field is given by

$E = \frac{Kq}{r^2}$

where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges

According to the diagram

BD = $\sqrt{2}\times a$

where, a be the side of the square

So, Electric field at B due to charge at A

$E_{A}=\frac{Kq}{a^2}$

$E_{A}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}$

EA = 6531.32 N/C

Electric field at B due to charge at C

$E_{C}=\frac{Kq}{a^2}$

$E_{C}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}$

Ec = 6531.32 N/C

Electric field at B due to charge at D

$E_{D}=\frac{Kq}{2a^2}$

$E_{D}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2\times 2.42^2}$

ED = 3265.66 N/C

Now resolve the components along X axis and Y axis

Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

The resultant electric field at B is given by

$E=\sqrt{E_{x}^{2}+E_{y}^{2}}$

$E=\sqrt{8840.5^{2}+8840.5^{2}}$

E = 12500 N/C

Explanation:

8 0

4 years ago

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Темирказык жулдызынын жулдыздык шамасы 2,02, ал Веганын жулдыздык шамасы 0,03. Осылардын кайсысы жарык жане неше есе жарык?

miv72 [106K]

Temirkazık ruled Myanmar value of about 2.02, Vega Funny 0.03. What is the orange light which of these factors times the light?

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3 years ago

2. How are electromagnets different from other magnets?

Stella [2.4K]

A magnet is made from materials that is magnetized and create its own persistent magnetic field while a electromagnet is mad from coil of wire which acts as a magnet when electric current passes through it.

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