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KATRIN_1 [288]
4 years ago
6

In hyperbolic geometry, an arc whose endpoints are on the edge of the Poincaré disk must be a line.

Mathematics
1 answer:
avanturin [10]4 years ago
4 0
It would to absolutely false to say that in hyperbolic geometry, an arc whose endpoints are on the edge of the <span>Poincaré disk must be a line. The correct option among the two options that are given in the question is the second option or option "B". I hope the answer comes to your help.</span>
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How to solve 14d-2d=-84
irinina [24]
First combine like terms:
14d+-2d=12d

Then do -84 divided by 12 = -7
D= -7


3 0
4 years ago
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vova2212 [387]
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6 0
3 years ago
Determine the number of pounds of nuts selling for $6 per pound and raisins selling for $3 per pound
Luda [366]
For the mix you need 60 Ib of nuts and raisins, and 60 lb of mix will sell for $300.
Let <em>x</em> be the weight of nuts and <em>y</em> the weight of raisins needed for the mix.
Total weight = <em>x</em>+<em>y</em> = 60, so <em>y</em> = 60 - <em>x</em>
Total value = 6<em>x</em> + 3<em>y</em> = 300.  From the above, we can substitute the <em>y</em> for 60 - x:
Total value = 6<em>x</em> + 3(60 - <em>x</em>) = 300, which we can simplify to:
6<em>x</em> + 180 - 3<em>x</em> = 300, and simplify again to:
3<em>x</em> = 120, and again to:
<em>x</em> = 40.  We can now calculate<em> y</em> from the first equation y = 60 - <em>x</em>, so:
y = 20.
40 lb of nuts and 20 lb of raisins.  Check:
40 lb x $6/lb = $240, and 20 lb x $3/lb = $60, $240 + $60 = $300.



7 0
3 years ago
The 2 in 324 is worth ten times the value of the 2 in 542
steposvetlana [31]
True; this statement is true.
8 0
4 years ago
Please help!!! 25 points!!
Eduardwww [97]
<h3>Answer: B) y = -x</h3>

==============================================

Work Shown:

g(x) = x^2-2

g(-2) = (-2)^2-2

g(-2) = 2

Saying (-2, g(-2)) is the same as saying (-2, 2)

---------------

g(x) = x^2-2

g(1) = 1^2 - 2

g(1) = -1

Saying (1, g(1)) is the same as saying (1, -1)

---------------

Let's find the slope of the line through (-2,2) and (1,-1)

m = (y2 - y1)/(x2 - x1)

m = (-1-2)/(1-(-2))

m = (-1-2)/(1+2)

m = -3/3

m = -1

Now turn to point slope form to find the equation

y - y1 = m(x - x1)

y - 2 = -1(x - (-2))

y - 2 = -(x + 2)

y - 2 = -x - 2

y-2+2 = -x-2+2 ... add 2 to both sides

y = -x

You could use the other point (1,-1) and you'd get the same answer. The slope m = -1 is the same each time.

7 0
4 years ago
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