Answer:
![f^{-1}(x)=\pm\sqrt{x+16}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Cpm%5Csqrt%7Bx%2B16%7D)
Step-by-step explanation:
![f(x)=x^2-16](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-16)
To find the inverse of this function, temporarily the f(x) with a y (or whatever else you want) and then solve for the x.
![y=x^2-16\\y+16=x^2\\x=\pm\sqrt{y+16}](https://tex.z-dn.net/?f=y%3Dx%5E2-16%5C%5Cy%2B16%3Dx%5E2%5C%5Cx%3D%5Cpm%5Csqrt%7By%2B16%7D)
Now, you can swap the variables again and write the function.
![f^{-1}(x)=\pm\sqrt{x+16}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Cpm%5Csqrt%7Bx%2B16%7D)
Answer:
Length = 16 inches and width = 12inches
Step-by-step explanation:
A = 192 in² . The width is 4 + 1/2x. therefore let x = length
Area = LW
192 = x(4 + 1/2 x)
192 = 4x + 1/2x²
384 = 8x + x² Multiply each term by 2 to make a
384 + 16 = x² + 8x + 16 Complete the square
400 = (x + 4)²
![\sqrt{400} = \sqrt{(x + 4)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B400%7D%20%3D%20%5Csqrt%7B%28x%20%2B%204%29%5E2%7D)
± 20 = x + 4
20 = x + 4 or -20 = x + 4
20 - 4 = x or -20 - 4 = x
16 = x or -24 = x reject the negative amount
Length = 16
width = 4 + 1/2(16); 4 + 8 = 12
14/20
14/18
1
7
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19 days are left in a year because 1 week=7 days which means 2 weeks=14 days 14 +5=19
Answer:
Remember that £ has a greater value compared to $ and vice versa.