the frequency (in hz) of these vibrations if the car moves at 24.2 m/s is 605 HZ .
Calculation :
frequency = ![\frac{number of contacts}{second}](https://tex.z-dn.net/?f=%5Cfrac%7Bnumber%20of%20contacts%7D%7Bsecond%7D)
frequency = ![\frac{24.2 m/s}{1}*100cm*\frac{1}{4cm}](https://tex.z-dn.net/?f=%5Cfrac%7B24.2%20m%2Fs%7D%7B1%7D%2A100cm%2A%5Cfrac%7B1%7D%7B4cm%7D)
= 605 HZ
Frequency describes the number of waves passing through a particular location in a particular time. So if the wave takes 1/2 second to travel, the frequency is 2 per second. If it takes 1/100th of an hour, the frequency is 100 per hour.
Frequency is the number of occurrences of a repeating event per unit time. ... sometimes called time-frequency for clarity,
Learn more about frequency here : brainly.com/question/254161
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Answer:
The minumum speed the pail must have at its highest point if no water is to spill from it
= 2.64 m/s
Explanation:
Working with the forces acting on the water in the pail at any point.
The weight of water is always directed downwards.
The normal force exerted on the water by the pail is always directed towards the centre of the circle of the circular motion.
And the centripetal force, which keeps the system in its circular motion, is the net force as a result of those two previously mentioned force.
At the highest point of the motion, the top of the vertical circle, the weight and the normal force on the water are both directed downwards.
Net force = W + (normal force)
But the speed of this motion can be lowered enough to a point where the normal force becomes zero at the moment the pail reaches the highest point of its motion. Any speed lower than this value would result in the water spilling out of the pail. The water would not be able to resist the force of gravity.
At this point of minimum velocity,
Normal force = 0
Net force = W
Net force = centripetal force = (mv²/r)
W = mg
(mv²/r) = mg
r = 0.710 m
g = 9.8 m/s²
v² = gr = 9.8 × 0.71 = 6.958
v = √(6.958) = 2.64 m/s
Hope this Helps!!!
Explanation:
4a)the displacement is the distance moved in a direction but since no direction is given, the displacement is equal to the distance
b) the distance moved is 400m because that's the length of the track
Answer:
![\omega=0.12\frac{rad}{s}](https://tex.z-dn.net/?f=%5Comega%3D0.12%5Cfrac%7Brad%7D%7Bs%7D)
Explanation:
In a uniform circular motion, since a complete revolution represents 2π radians, the angular velocity, which is defined as the angle rotated by a unit of time, is given by:
![\omega=\frac{2\pi}{T}(1)](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B2%5Cpi%7D%7BT%7D%281%29)
Here T is the period, that is, the time taken to complete onee revolution:
![T=\frac{2\pi r}{v}(2)](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B2%5Cpi%20r%7D%7Bv%7D%282%29)
Replacing (2) in (1):
![\omega=\frac{2\pi}{\frac{2\pi r}{v}}=\frac{v}{r}\\\omega=\frac{19.1\frac{m}{s}}{158m}\\\omega=0.12\frac{rad}{s}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B2%5Cpi%7D%7B%5Cfrac%7B2%5Cpi%20r%7D%7Bv%7D%7D%3D%5Cfrac%7Bv%7D%7Br%7D%5C%5C%5Comega%3D%5Cfrac%7B19.1%5Cfrac%7Bm%7D%7Bs%7D%7D%7B158m%7D%5C%5C%5Comega%3D0.12%5Cfrac%7Brad%7D%7Bs%7D)
'A' is correct. B, C, and D are false statements.