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lawyer [7]
3 years ago
9

What causes the rider on a roller coaster to experience the + or - g’s if gravity always remains the same on earth

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

Yes both = and - g can be felt by a rider in a roller coaster.

Explanation:

It is crucial to understand how we feel gravity in this case.

We humans have no sensory organs to directly detect magnitude and direction like some birds and other creatures, but then how do we we feel gravity?

When we stand on our feet we feel our weight due to the normal reaction of floor on our feet trying to keep us stand and our weight trying to crush us down. In an elevator we feel difference in our weight (difference magnitudes of gravity) but actually we are feeling the differences in normal reactions under different accelerations of the elevator.

In the case of roller coaster you will feel +g as you  sit on a chair in it, but will feel -g when you are in upside down position as roller coaster move.

When you are seated you will feel the normal reaction of seat on you giving you the feeling +g and the support of the buckles to stay in the roller coaster when you are upside down will give you the -g feeling.

<u>This is just the physics approach</u>, a biological approach can be given in association with sensors relating to ears.

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Answer:

Option A

The apparent change in frequency of waves due to the motion of a source

Explanation:

Doppler effect is the apparent change in frequency of waves due to the motion of a source. Doppler effect occurs when the source of waves moves towards the observer which causes emission of successive wave crests to be closer to the observer compared to the previous wave crest. This phenomenon was named after Austrian Physicist called Christian Doppler

4 0
3 years ago
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Convert 1 second in to solar day<br>​
jeka94

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8 0
4 years ago
) a 1.0 kilogram laboratory cart moving with a velocity of 0.50 meter per second due east collides with and sticks to a similar
ZanzabumX [31]
Momentum would be the same before and after the collision
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 0.25 * (1 + 1) =
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4 0
4 years ago
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The repulsive force between two protons has a magnitude of 2.00 N. What is the distance between them?
Aloiza [94]

Answer:

The answer to your question is letter A.     r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

                 F = K\frac{q1q2}{r^{2}}

Solve for r

                r = \sqrt{\frac{kq1q2}{F}}

Substitution

                r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}

Simplification

                r = \sqrt{\frac{2.3 x 10^{-28}}{2}}

                r = \sqrt{1.15 x 10^{-24}}

Result

                r = 1.07 x 10⁻¹⁴ m

6 0
3 years ago
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When a force of 450N pushes on a 20kg box as
ehidna [41]

Answer:

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Explanation:

7 0
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