NEED HELP PLEASE
1 answer:
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The formula for nCk is ...
nCk = n!/(k!(n -k)!)
It always works out that nC0 = 1 and nC1 = n, and the sequence of numbers across a row of the diagram is symmetrical about the center.
This means you only need to calculate one value to finish filling your diagram.
4C2 = 4!/(2!(2!)) = (4·3)/(2·1) = 6
You will find the pattern to be ...
each element in the diagram is the sum of the two above it.
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Answer:
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 590 hours.
This means that
Find the probability of a bulb lasting for at most 605 hours.
This is the pvalue of Z when X = 605. So
has a pvalue of 0.8413
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.