Answer:
q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.
Explanation:
The Specific Heat capacity of Lead is 0.128 
This means, increase in temperature of 1 gm of lead by 
will require 0.128 J of heat.
Formula Used :
q = amount of heat added / removed
m = mass of substance in grams = 85.0 g
c = specific heat of the substance = 0.128
= Change in temperature
= final temperature - Initial temperature
= 10 - 200
= -
put value in formula
q = - 
On calculation,
q = - 2067.2 J
- sign indicates that the heat is released in the process
It would have a zero charge because it is a neutral atom. The number of electrons which is a negative charge is equal to the number of protons which is positive, they will cancel each other out hence meaning it will become neutral
The serving of peanut butter contains 117kcal
<h3>Calculation of calories of food Nutrients</h3>
1 gram of both carbohydrate and protein contains 4 (kcal)
1 gram of fat contains 9 (kcal)
But peanut butter contains 5g of fat. The kilocalories of fat present is;
1 g = 9 kcal
5g = F
F = 5×9
F = 45 kcal
The kilocalories of carbohydrates present is;
1g = 4kcal
12g = C
C= 12×4
C = 48kcal
The kilocalories of proteins present is;
1g = 4kcal
6 g = P
P = 4× 6
P = 24 kcal
Therefore, the total kilocalories of the peanut = 45 + 48 + 24 = 117kcal
Learn more about kilocalories here:
brainly.com/question/6423812
