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Katarina [22]
3 years ago
9

What is the gram formula mass of NazC03

Chemistry
1 answer:
kotykmax [81]3 years ago
7 0

Answer:

84,007 g/mol

Explanation:

Molar mass of NazCO3 which is Sodium Bicarbonate (NaHCO₃) is 84,007 g/mol

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What way do S waves move
BlackZzzverrR [31]
S waves shake the ground in a shearing, or crosswise, motion that is perpendicular to the direction of travel. These are the shake waves that move the ground up and down or from side to side.
4 0
9 months ago
When barium becomes positively charged, it forms a(n): (2 points)
mart [117]

Barium forms cation : Ba²⁺

<h3>Further explanation</h3>

Given

Barium element

Required

Ion type

Solution

Barium with the symbol Ba is an alkaline earth metal element having the atomic number 56

Electron configuration of Barium: [Xe] 6s2

If we look at this configuration, then Barium will try to achieve stability by removing 2 electrons so that the electron configuration is the same as the noble gas Xenon (Xe)

Because it removes 2 electrons, Barium has the number of protons> the number of electrons so that the charge is positive and forms a cation

3 0
2 years ago
The atomic number is the number of protons in the atom of the element
ipn [44]

Answer:

True

Explanation:

If you look closley at the nucleus, you don't count the neutrons just the prtons which then effect the electrons.

Good luck :)

5 0
3 years ago
A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca
umka21 [38]

Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0
3 years ago
Could the Periodic Table be arranged differently?
coldgirl [10]

Answer:

No because it is stayed that way and you can't define them differently.

7 0
3 years ago
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