Answer: I think the formula is PV=nRT and I divide both sides by RT, but this is as far as I can get in my equation before I get stumped: (751 mm Hg) (8.3 L)/ (309 K) Can you help?
Explanation:
Answer:
-2024 kJ
Explanation:
The combustion of propane is
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g)
And, ΔG° = ΔH° - TΔS°
Where T is the temperature in K.
ΔH° = ∑n*H°f, reactants - ∑n*H°f, products
Where n is the number of moles in the stoichiometry reaction. H°f, O₂(g) = 0 because it's a substance formed by only one element.
ΔH° = [4*(-226) +3*(-398)] - [-100] = -1998 kJ
ΔS° = ∑n*S°, reactants - ∑n*S°, products
ΔS° = [4*(184) + 3*214] - [5*204 + 271] = 87 J/K = 0.087 kJ/K
So
ΔG° = -1998 - 298*0.087
ΔG° = -2024 kJ
False, I’m going from what I know but if it’s correct pls heart this
Answer:
part a: How much of the isotope will you have left after 10 years?
part b: How much of the isotope will you have left after 20 years?
part c: How many half-lives will occur in 40 years?
