0.05 * V1 = 250 * 10
<span> V1 = 2500 / 0.05 </span>
<span> V1 = 2500 * 20 </span>
<span> V1 = 50000 mL </span>
<span>V1 = 50 Liters .
Hope this helped! :3</span>
The temperature change is 23 °C.
<em>q = mC</em>Δ<em>T</em>
Δ<em>T</em> = <em>q</em>/(<em>mC</em>)
<em>m</em> = 355 g
∴ Δ<em>T</em> = (34 000 J)/(355 g × 4.184 J·°C⁻¹g⁻¹) = 23 °C
<em>Note</em>: The answer can have only <em>two significant figures</em> because that is all you gave for the amount of heat absorbed.
First you need to find the mass of one mole of the element. (say Fe)
Find Fe on the periodic table, it should tell you what the average atomic mass is.
The average atomic mass = mass of one mole.(in this case it is 55.85g)
Take your moles (1.35mol Fe) and multiply it by the mass of one mole (55.85g)
1.35mol*55.85g/mol=75.39g
(Just repeat that method for the other problems) use the formula <span><span>moles=<span><span>mass</span><span>Molar mass
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