Express M=cos3A + cos A and N = sin3A + sin A as a product form
1 answer:
Answer:
2cosAcos2A, 4sinAcos^2A
Step-by-step explanation:
cos3A+cosA
2cos((3A+A)/2)cos((3A-A)/2)
2cos(4A/2)cos(2A/2)
2cosAcos2A
sin3A+sinA
2sin((3A+A)/2)cos((3A-A)/2)
2sin(4A/2)cos(2A/2)
2sin2AcosA
4sinAcos^2A
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Step-by-step explanation:
Answer is 18
Step by step explanation
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