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Rom4ik [11]
2 years ago
6

YALL PLSSSSSSSS HELP IM SHAKING I NEED HELP PLSS

Mathematics
1 answer:
Vilka [71]2 years ago
8 0

Answer:

someone is adding dont worrie

Step-by-step explanation:

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Terrell used wired fencing to form a border around a circular region vin his backyard. If the radius of the circular region was
eimsori [14]

Answer:

  37.7 yd

Step-by-step explanation:

The circumference of a circle can be found using the formula ...

  C = 2πr

For a radius of 6 yd, the circumference is ...

  C = 2π(6 yd) = 12π yd ≈ 37.7 yd

The length of the circular border was 37.7 yards.

5 0
2 years ago
E bisects line segment df. df=2y, and ef=8y-3. find de, ef, and df.
Usimov [2.4K]

1/2DF = EF

1/2(2y) = 8y - 3

  • Multiply 1/2 * 2y.

y = 8y - 3

  • Subtract 8y from both sides.

-7y = -3

  • Divide both sides by -7.

y = 3/7

  • Plug 3/7 for y into DF and EF.

DF: 2(3/7) = 6/7

EF: 8(3/7) - 3 = 24/7 - 3 = 3/7

EF = DE because they are bisected, so DE = 3/7

8 0
3 years ago
-7w=-w+6<br><br> Please help what does this equal to
Over [174]
It equals -1
you have collect like terms the -7w+w
which give you -6w then you have to divide both sides by -6
which gives you -1
4 0
2 years ago
Can someone pls help I need help ASAP
almond37 [142]

all correct choices are as follows: a, b, c

3 0
2 years ago
12. Ronnie Cox just inherited $27,000. How much of this money should he set aside today to have $17,000 to pay cash for a Ventur
AlekseyPX

Answer:

Amount to be kept separately for having $17,000 at year end = $16,715.83

Step-by-step explanation:

As it is provided, that annual return = 1.7% compounded annually.

We need to calculate the amount to be invested today, to get a total of $17,000 at year end.

Since the interest is compounded annually, it is a simple interest if the term is of 1 year.

Therefore,

Investment  + Investment \times 1.7% = $17,000

Investment + 0.017 Investment = $17,000

1.017 Investment = $17,000

Investment = \frac{17,000}{1.017} = 16,715.83

Therefore, Investment today = $16,715.83

5 0
2 years ago
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