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statuscvo [17]
3 years ago
10

The difference between -7 and a number x is no more than -2/3

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

Pregunta muy difícil, no creo que pueda resolver este amigo.

Step-by-step explanation:there is no step-by-step thing because honestly don't understand what your trying to say here. Hmm...

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The odds of an individual getting struck by lightening in one year are roughly 1 in a million; for this question assume this pro
Montano1993 [528]

Answer:

There is a 5*10^{-9}% probability that exactly 2 of them are hit by lightening in a given year

The correct probability distribution to solve this problem is the binomial probability.

This is exact the type of problem that the binomial probability is used, when we want to find the probability of a exact number of events happening in a number of trials.

Step-by-step explanation:

Here we use the binomial probability.

For the binomial probability calculus we have these following parameters.

n: The number of repeated trials

x: The desired number of sucesses.

p: The probability of success on each individual trial.

The probability of exactly x sucesses on n repeated trials is given by:

P = C_{n,x}.p^{x}.(1 - p)^{n-x}

In which C_{n,x} is the combination of the number of repeated trials and the desired number of sucesses. The combination formula is given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

Here we have:

Sample of eleven people, so n = 11

Exactly two of them being hit, so x = 2

p = 10^{-6}

The probability that exactly two people are hit by a lightning is:

P = C_{n,x}.p^{x}.(1 - p)^{n-x}

P = C_{11,2}.(10^{-6})^{2}.(1 - 10^{-6})^{9}

P = 55.(10^{-6})^{2}.(1 - 10^{-6})^{9}

P = 5*10^{-11}

Multiplying by 100, to write in percent notation.

There is a 5*10^{-9}% probability that exactly 2 of them are hit by lightening in a given year

8 0
3 years ago
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