Answer:
Q = 160.36[kJ], is the heat lost.
Explanation:
This is a thermodynamic problem where we can find the latent heat of vaporization, at a constant temperature of 100 [°C].
We know that for steam at 100[C], the enthalpy is
For liquid water at 100[C], the enthalpy is
Therefore
The amout of heat is given by:
The magnitude of the tangential acceleration of the hanging mass is 2mg/MR
<h3>Tangential acceleration of the hanging mass</h3>The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;
τ = Iα
Where;
Where;
The tangential acceleration is calculated as follows;
Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR
Learn more about tangential acceleration here: brainly.com/question/11476496