I don't have research to back it up, but exercise is working out. Fitness is taking care of your body, that includes working out and things like eating right.
Answer:
B) False.
Explanation:
Most of the times, the numbers that appears right to the cursor are representing the coordinates (x & y) of the cursor. So as the cursor moves around the screen those number changes accordingly.Therefore its wrong to say that there is no need to add a dimension to set the dimensional value.
Answer:
The correct answer is - A matter that has an ordered arrangement of atoms, molecules, or ions.
Explanation:
In physics, a crystal is a type of solid matter in which a highly arranged molecule or atoms present to form a lattice that extended in all directions. It is a lightweight clear solid which is normally is colorless.
It can be cubic, hexagonal, triclinic, monoclinic, orthorhombic, tetragonal, and trigonal that are ordered arrangments. Its internal symmetry is visible to its surface.
Answer:
E=![\frac{KQ}{2\sqrt 2a^2}](https://tex.z-dn.net/?f=%5Cfrac%7BKQ%7D%7B2%5Csqrt%202a%5E2%7D)
Explanation:
We are given that
Charge on ring= Q
Radius of ring=a
We have to find the magnitude of electric filed on the axis at distance a from the ring's center.
We know that the electric field at distance x from the center of ring of radius R is given by
![E=\frac{kQx}{(R^2+x^2)^{\frac{3}{2}}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BkQx%7D%7B%28R%5E2%2Bx%5E2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D)
Substitute x=a and R=a
Then, we get
![E=\frac{KQa}{(a^2+a^2)^{\frac{3}{2}}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BKQa%7D%7B%28a%5E2%2Ba%5E2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D)
![E=\frac{KQa}{(2a^2)^{\frac{3}{2}}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BKQa%7D%7B%282a%5E2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D)
![E=\frac{KQa}{2\sqrt 2a^3}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BKQa%7D%7B2%5Csqrt%202a%5E3%7D)
![E=\frac{KQ}{2\sqrt 2a^2}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BKQ%7D%7B2%5Csqrt%202a%5E2%7D)
Where K=![9\times 10^9 Nm^2/C^2](https://tex.z-dn.net/?f=9%5Ctimes%2010%5E9%20Nm%5E2%2FC%5E2)
Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=![\frac{KQ}{2\sqrt 2a^2}](https://tex.z-dn.net/?f=%5Cfrac%7BKQ%7D%7B2%5Csqrt%202a%5E2%7D)