Answer:
2.80 MJ
Explanation:
(a) We want to calculate the energy U of the battery, where its voltage is E = 13.0V and the supplied current is I = 60 A. We can neglect the internal resistance, so the terminal voltage equals the emf of the battery V = 13.0V. The quantity of delivered energy is given by the rate at which energy is delivered to it in a certain time t. We could obtain the rate at which energy is transferred by using equation , where the rate represents the power P = IV. Therefore, the energy produced is given by
U = P*t (P = IV)
U = I*V*t (1)
Now we can plug our values for I, V and t into equation (1) to get the energy produced in time t = 1 h = 3600 s
U = I*V*t = (60 A)(13 V)(3600s) = 2.80 MJ
Answer:
All kinds of waves have the same fundamental properties of reflection, refraction, diffraction, and interference, and all waves have a wavelength, frequency, speed, and amplitude.
Explanation:
Momentum is described as the result of the calculation of mass multiplied by that thing's velocity.
<span>
In equational formula we can write it: </span>
<span>
P (momentum) = m(mass) * v(velocity) </span>
so to find the mass, revert the equation:
<span>
P = m v </span>
m = P / v
now for the value entry,
<span>
m = 2.5 * 10^4 kgm/s / 30 m/s </span>
<span>
m = 8,3 * 10^2 kilograms
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
The answer would be B because humans cannot see electrons so we visualize the electrons due to the theory
Answer:
a) The mass flow rate through the nozzle is 0.27 kg/s.
b) The exit area of the nozzle is 23.6 cm².
Explanation:
a) The mass flow rate through the nozzle can be calculated with the following equation:

Where:
: is the initial velocity = 20 m/s
: is the inlet area of the nozzle = 60 cm²
: is the density of entrance = 2.21 kg/m³
Hence, the mass flow rate through the nozzle is 0.27 kg/s.
b) The exit area of the nozzle can be found with the Continuity equation:



Therefore, the exit area of the nozzle is 23.6 cm².
I hope it helps you!