Answer:
Critical value f(1)=2.
Minimum at (1,2), function is decreasing for and increasing for
is point of inflection.
When 0<x<3, function is concave upwards and when x>3, , function is concave downwards.
Step-by-step explanation:
1. Find the domain of the function f(x):
2. Find the derivative f'(x):
This derivative is equal to 0 at x=1 and is not defined at x=0. Since x=0 is not a point from the domain, the crititcal point is only x=1. The critical value is
2. For the derivative f'(x)<0, then the function is decreasing. For the derivative f'(x)>0, then the function is increasing. This means that point x=1 is point of minimum.
3. Find f''(x):
When f''(x)=0, x=3 and
When 0<x<3, f''(x)>0 - function is concave upwards and when x>3, f''(x)>0 - function is concave downwards.
Point is point of inflection.
Answer:
The y-intercept of line A is 6 and the y-intercept of line B is 6. Basically y-intercept is the y variable and in this case 6 is the y variable (0, 6). This means that line A and line B are the same. Not sure what options you have in the end but they are the same. Hope this helps, thank you :) !!
Answer:
likely
Step-by-step explanation:
Answer:
p = -8x - 29/ x
Step-by-step explanation:
Let's solve for p.
px=(−4)(6)+(2)(5)−8x−15
Step 1: Divide both sides by x.
px
x
=
−8x−29
x
p=
−8x−29
x
Answer:
53
Step-by-step explanation: