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3 years ago

15

Please help! I will give Brainliest! Who is correct?

1 answer:

soldi70 [24.7K]3 years ago

8 0

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say I love you

Step-by-step explanation:

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Parth created a Box-and-Whisker Plot to show the average weight of the fish he caught over the weekend. What information does th

german

B. beacuse the middle wieght of the fish

6 0

2 years ago

What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?

Darya [45]

Answer:

$4 \sqrt{2} i$

Step-by-step explanation:

We want to find the sum of

$\sqrt{ - 2} + \sqrt{ - 18}$

We can rewrite this as

$\sqrt{ 2 \times - 1} + \sqrt{ 18 \times - 1}$

This becomes;

$\sqrt{2} \times \sqrt{ - 1} + \sqrt{18} \times \sqrt{ - 1}$

Recall that;

$i = \sqrt{ - 1}$

This implies that;

$\sqrt{2} i + 3 \sqrt{2} i$

Combine like terms:

$4 \sqrt{2} i$

3 0

3 years ago

Evaluate the expression xy-3x; when x=4 and y=5. Pls provide explanation. Will choose brainliest.

Iteru [2.4K]

4*5-3*4

20-12

=8

Just plug in the numbers and solve. Remember that you multiply before you subtract.

7 0

3 years ago

Sally walked 3/4 of a mile before lunch and 1/2 of a mile after lunch. How far did she walk in all?

Wittaler [7]

Answer:

1 1/4

Step-by-step explanation:

5 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

shusha [124]

Answer:convergent

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int_{-\infty}^{0}1000e^xdx$

$I=1000=\int_{-\infty}^{0}e^xdx$

integration of $e^x$ is $e^x$

$I=1000\times \left [ e^x\right ]^{0}_{-\infty}$

$I=1000\times I=\left [ e^0-e^{-\infty}\right ]$

$I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]$

$I=1000\times 1=1000$

so the integration converges to 1000 units

6 0

3 years ago