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Sergeu [11.5K]
3 years ago
12

I need help pleaseee

Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

6p = c

Step-by-step explanation:

Graph:

6p=c

p is x and c is y

If x=1, y= 6. (1,6)

If x=2, y= 12. (2,12)

If x=3, y= 18. (3,18)

Plot the points and draw the line.

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What is the slope of a line perpendicular to the<br> graph of the equation 5x - 3y = 2?)
Advocard [28]

The slope of a line perpendicular to the

graph of the equation 5x - 3y = 2 is -3/5.

<h3>How to find the slope of a line?</h3>

given that the equation is 5x - 3y = 2.

now write the equation in standard form y = mx + b

then -3y = 2 - 5x

y = -2/3 + 5x/3

y = 5/3x - 2/3

m 1*m 2 = - 1 is the formula for the slopes from a pair of perpendicular lines. where the slopes of the lines are m 1 and m 2.

Here m1 = 5/3 and m2 = -3/5.

Hence,the slope of a line perpendicular to the

graph of the equation 5x - 3y = 2 is -3/5.

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3 0
1 year ago
I need help please. Trying to get my HS diploma. I did not graduate :(
grigory [225]

The graph of f(x) + 1 is the graph in the option C.

<h3>Which is the graph of f(x) + 1?</h3>

For a given function f(x), a vertical translation is written as:

g(x) = f(x) + N

  • If N > 0, then the translation is upwards.
  • If N < 0, then the translation is downwards.

Here we have g(x) = f(x) + 1, so we have a translation of 1 unit upwards, the graph of f(x) + 1 is the graph of f(x) but translated one unit upwards.

From that, we conclude that the correct option is C.

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3 0
2 years ago
A nutritionist would like to estimate the number of times adults exercise each week. To collect information, the nutritionist em
enot [183]

Answer:

Step-by-step explanation:

c

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3 years ago
Ao se olhar para a história da Álgebra, desde os primórdios quando o objeto de estudo eram equações algébricas específicas até o
professor190 [17]

Answer:

44

Step-by-step explanation:

Trust

8 0
3 years ago
5. Solve for x using any method you'd like. Round to the hundredth. Show all your work. (2 points each) d. 20x^3 = 7x^5
Sindrei [870]

Solving this equation for x, we have:

\begin{gathered} 20x^3=7x^5 \\ 7x^5-20x^3=0 \\ x^3(7x^2-20)=0 \\ \begin{cases}x^3=0\to x=0 \\ 7x^2=20\to x=\pm\sqrt[]{\frac{20}{7}}\end{cases} \end{gathered}

6 0
1 year ago
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