We need to convert the mixed fractions into improper fractions.
1*8 = 8
8+7 = 15
15/8
2*3 = 6
6+1 = 7
7/3
Now we can finish and multiply
15*7 = 105
8*3 = 24
Simplify 105/24
105/24
24*4 = 96
105 - 96 = 9
4 is the whole number, and 9 is the numerator.
4 9/24
Simplify that,
9/3 = 3
24/3 = 8
4 3/8
Answer: 
Answer:48 16 = ?
27 9 = 9
60 20 - 10
Step-by-step explanation:
Answer:
-1 and 5
Step-by-step explanation:
Answer:
A), B) and D) are true
Step-by-step explanation:
A) We can prove it as follows:
B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that 
. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then 
.
C) Consider 
. This set is orthogonal because 
, but S is not orthonormal because the norm of (0,2) is 2≠1.
D) Let A be an orthogonal matrix in 
. Then the columns of A form an orthonormal set. We have that 
. To see this, note than the component 
of the product 
is the dot product of the i-th row of 
and the jth row of 
. But the i-th row of is equal to the i-th column of . If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then 
E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.
In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set 
and suppose that there are coefficients a_i such that 
. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then 
then 
.
It would be mean. The mean is the average that is you are looking for, since she wants a summerization of all the values in the data set. To find the mean (average) add all the numbers and then divide by the amount of numbers.
