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3 years ago

7

PLEASE HELP As you can see in the photo I have been doing it but I don't know if it's okay, can you tell me if it's okay and if

you can't help me do it pleaseeee !!!

1 answer:

pishuonlain [190]3 years ago

3 0

It is not it would turn towards your left on the left wide side

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Accounts Payable had a normal starting balance of $800. There were debit postings of $600 and credit postings of $300 during the

sasho [114]

The normal balance of an accounts payable is credit.
So you start with $800-cr
Any debit posting will reduce that normal balance and any credit posting will increase the normal balance.

The $600 debit posting will create a $200 credit balance(800-600)

The $300 credit posting will create a $500 credit balance(300+200)

Answer: A. $500 - Credit.

It may help to figure it out if you create a t-chart and enter the amounts.

3 0

3 years ago

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒ $\lambda_2=\frac{4L}{3}$ ⇒ $\lambda_3=\frac{4L}{5}$

⇒ $\lambda_2=\frac{4(120)}{3}$ ⇒ $\lambda_3=\frac{4(120)}{5}$

⇒ $\lambda_2=\frac{480}{3}$ ⇒ $\lambda_3=\frac{480}{5}$

⇒ $\lambda_2=160\ cm$ ⇒ $\lambda_3=96\ cm$

So the pipe is open at one end and closed at one end .

6 0

3 years ago

PLEASE HELP ME ASAP!

AleksandrR [38]

Ok so first we find the equation that equals one variable.

2y = -x + 9

3x - 6y = -15

We solve for y.

2y = -x + 9

y = -x/2 + 9/2

Then we plug in this y value into the other equation to keep only one variable so we can solve for it.

3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18

Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.

y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3

Your answer would be (-28/3, -3/18)

Hope this helps!

6 0

4 years ago

Read 2 more answers

Three orders are placed at a pizza shop. two small pizzas, a liter of soda, and a salad cost $14; one small pizza, a liter of so

mojhsa [17]

To determine the cost of each item, we need to set up equations. From the problem statement, we have three unknowns so we need three equations. We set up equations as follows:

let x cost of small pizzas
y cost of soda
z cost of salad

two small pizzas, a liter of soda, and a salad cost $14
2x + y + z = 14

one small pizza, a liter of soda, and three salads cost $15

x + y + 3z = 15

three small pizzas, a liter of soda, and two salads cost $22
3x + y + 2z = 22

Solving for x, y and z, we will have:

x = $ 5
y = $ 1
z = $ 3

6 0

3 years ago

Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1

Digiron [165]

Answer:

$P(z$

And the best option would be:

$0.8708$

Step-by-step explanation:

We assume that the distribution for the random variable is:

$X \sim N (\mu=0 , \sigma=1)$

For this case we want to calculate the following probability:

$P(z$

And we can use the normal standard distribution or excel and we got:

$P(z$

And the best option would be:

$0.8708$

8 0

3 years ago