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sesenic [268]
3 years ago
6

What is the correct formula name of BaH2​

Chemistry
2 answers:
rodikova [14]3 years ago
6 0
Answer: Barium Hydride
sashaice [31]3 years ago
6 0
Barium hydride (BaH2)
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In a chemical change
Lana71 [14]

Answer:

Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. These processes are called chemical reactions and, in general, are not reversible except by further chemical reactions.

Explanation:

4 0
3 years ago
Convert 22 ml in to liters
prisoha [69]

Answer:

0.022

Explanation:

milliter (ml) = 1 cubic centimeter (cc)= 0.001 liters (l) = 0.000001 cubic meters (m3).

1 ml = 0.061024 cubic inches (in3) ; 1 in3 = 16.4 ml.

1 ml = 0.000035 cubic feet (ft3); 1 ft3 = 28,317 ml.

1 ml = 2.64 x 10-4 U.S. gallons (gal); 1 gal = 4.55 x 103 ml.

8 0
3 years ago
How many valence electrons does magnesium (Mg) have?Question options:A) 6B) 2C) 12D) 0
wel

INFORMATION:

We must find the number of valence electrons for magnesium

STEP BY STEP EXPLANATION:

In order to know the number of valence electrons for Mg, we need to locate the element in the periodic table

Since Mg is in the second group of the periodic table, it has two valence electrons.

ANSWER:

B) 2

4 0
1 year ago
How many atoms of S are in the following formula: 3Na(SO4)2<br><br> 1) 6<br> 2) 8<br> 3) 3<br> 4) 5
larisa [96]

Answer:

6

Explanation:

7 0
3 years ago
How much heat, in joules, is required to warm a metal disc from 19 °C to 33 °C? The
zalisa [80]

Answer:

Q = 96.6 j

Explanation:

Given data:

Heat required = ?

Initial temperature = 19°C

Final temperature = 33°C

Mass of disc = 3.0 g

Specific heat capacity = 2.3 J/g.°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 33°C - 19°C

ΔT = 14°C

Q = 3.0 g×2.3 J/g.°C × 14°C

Q = 96.6 j

3 0
3 years ago
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