Answer:
3.5 hours
Step-by-step explanation:
Speed of train X=30 mph
Speed of train Y=40 mph
Relative speed When the two trains travelling in same direction
Relative speed=40-30=10 mph
Total distance =25+10=35 miles
We have to find the time when train Y is 10 miles ahead of train X.
We know that
Time=![\frac{Distance}{Relative\;speed}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%7D%7BRelative%5C%3Bspeed%7D)
Using the formula
Then, we get
Time=![\frac{35}{10}=3.5 hours](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B10%7D%3D3.5%20hours)
Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.
Answer:
sec A = 5/4
Step-by-step explanation:
Sec of an angle is hypotenuse/adjacent side
In your problem, sec A = 25/20 = 5/4
It helps if you can draw a figure of the problem. Make sure you memorize the definition of each trig function
Answer:
KL= 17.67 unit
UE = 17.67 unit
Step-by-step explanation:
Given:
Diagonals
KL= h+7
UE = 4h-25
Find:
Length of diagonals KL and UE
Computation:
We know that in isosceles trapezoid the length of diagonals are equal
So,
KL = UE
h+7 = 4h-25
3h = 32
h = 10.67
So,
KL= h+7
KL= 10.67+7
KL= 17.67 unit
UE = 4h-25
UE = 4(10.67)-25
UE = 17.67 unit
12 subtracted by 33 divided by 4 equals 3.75