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lesya [120]
3 years ago
10

-2(x + 3) = -2(x + 1) - 4​

Mathematics
1 answer:
ratelena [41]3 years ago
4 0
I’m working on something like that now
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What is the slop-intercept of the line that passes through the points (7,-5) and (3,-9)?
bagirrra123 [75]

\bf (\stackrel{x_1}{7}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-9}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-9-(-5)}{3-7}\implies \cfrac{-9+5}{-4}\implies \cfrac{-4}{-4}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=1(x-7) \\\\\\ y+5=x-7\implies y=x-12

4 0
4 years ago
Antonio used 16 1/3 cups of flour to make banana bread. The recipe for one loaf of banana bread calls for 2 1/3 cups of flour. W
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6 0
3 years ago
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Evaluate x2y for x = -3 and y = 2
padilas [110]
-3*2*2 = - 12
Multiply all to get the answer
8 0
4 years ago
Solve the following equation. Show all your work.
horrorfan [7]
\dfrac{x}{x - 2} + \dfrac{x - 1}{x + 1} = -1

(x - 2)(x + 1) \times \dfrac{x}{x - 2} + (x - 2)(x + 1) \times \dfrac{x - 1}{x + 1} = -1(x - 2)(x + 1)

(x + 1)x + (x - 2)(x - 1) = -1(x - 2)(x + 1)

x^2 + x + x^2 - 3x + 2 = -x^2 + x + 2

3x^2 - 3x = 0

3x(x - 1) = 0

x = 0~~~or~~~x - 1 = 0

x = 0 ~~~ or ~~~ x = 1


Since neither 0 nor 1 cause a zero in a denominator in the original equation, 0 and 1 are acceptable as solutions.

Answer: x = 0 or x = 1



8 0
3 years ago
What x value solves the equation?<br> 3x - 5 = 1<br> x=
strojnjashka [21]

Answer:

x = 2

Step-by-step explanation:

Step 1: Write equation

3x - 5 = 1

Step 2: Solve for <em>x</em>

  1. Add 5 to both sides: 3x = 6
  2. Divide both sides by 3: x = 2

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

3(2) - 5 = 1

6 - 5 = 1

1 = 1

8 0
3 years ago
Read 2 more answers
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