Answer:
0,040 M
Explanation:
The global reaction of the problem is:
Al(OH) (s) + OH⁻ ⇄ Al(OH)₂⁻(aq) K= 40
The equation of equilibrium is:
K = ![\frac{[Al(OH)_{2} ^-]}{[Al(OH)][OH^-]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAl%28OH%29_%7B2%7D%20%5E-%5D%7D%7B%5BAl%28OH%29%5D%5BOH%5E-%5D%7D)
The concentration of OH⁻ is:
pOH = 14 - pH = <em>3</em>
pOH = -log [OH⁻]
[OH⁻] = 1x10⁻³
Thus:
40 = ![\frac{[Al(OH)_{2} ^-]}{[Al(OH)][1x10^{-3}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAl%28OH%29_%7B2%7D%20%5E-%5D%7D%7B%5BAl%28OH%29%5D%5B1x10%5E%7B-3%7D%5D%7D)
<em>0,04M = ![\frac{[Al(OH)_{2} ^-]}{[Al(OH)]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAl%28OH%29_%7B2%7D%20%5E-%5D%7D%7B%5BAl%28OH%29%5D%7D)
</em>
This means that 0,04 M are the number of moles that the solvent can dissolve in 1L, in other words, solubility.
I hope it helps!
Oh wow , what grade are you in ukliblo ?
The correct formula of the oxide that forms when X burns in oxygen is X2O3.
Ionization energy is defined as the energy required to remove an electron from an atom. There are as many ionization energies present in an atom as there are electrons in that atom.
However, we can know the ionization energy values that belong to electrons in the outermost shell because they lie close together. If we go further into the inner shells, there is a sudden quantum jump in ionization energy values.
The element X must have three valence electrons because 631 ,1235, 2389 all refer to ionization energies of electrons in the valence shell. As we get into a core shell, there is a sudden jump hence the fourth and fifth ionization energies are 7089 and 8844 respectively.
The correct formula of the oxide that forms when X burns in oxygen is X2O3.
Learn more: brainly.com/question/16243729
When blue vitriol is heated, those water of crystallization escape out of the crystal and what's left is anhydrous copper sulphate or simply CuSO4, without any water of crystallization.
