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Ber [7]
3 years ago
13

HELP ME WITH THIS PLEASE

Mathematics
2 answers:
castortr0y [4]3 years ago
3 0

#Guitar 1

  • SP=160
  • CP=100

change=160-100=60

Percent :-

\\ \sf\longmapsto \dfrac{60}{160}\times 100

\\ \sf\longmapsto 37.5\%

#Guitar 2

  • SP=250
  • CP=150

Change=250-150=100

Percent:-

\\ \sf\longmapsto \dfrac{100}{250}\times 100

\\ \sf\longmapsto 40\%

Option B is correct

SpyIntel [72]3 years ago
3 0

Answer:

The second guitar has a greater percent change of approximately 40%.

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mario62 [17]

Answer:

n = 13

Step-by-step explanation:

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\frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

<u>Experimental probabilities from the table:</u>

Probability of getting 1 = \frac{12}{60}=\frac{1}{5}

Probability of getting 2 = \frac{17}{60}

Probability of getting 3 = \frac{15}{60}=\frac{1}{4}

Probability of getting 4 = \frac{16}{60}=\frac{4}{15}

<u>To determine which are the experimental probabilities from the table:</u>

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: \frac{17}{60}

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: \frac{1}{4}

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: \frac{7}{15}

This is not obtained above. So, it is not the experimental probability.

Option E: \frac{12}{43}

This is not obtained above. So, it is not the experimental probability.

Hence \frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

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