1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VLD [36.1K]
2 years ago
7

Construct an inscribed circle in triangle PQR by finding the incenter of the triangle.

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
6 0

Answer:

i dont know SORRY

Step-by-step explanation:

You might be interested in
Which of the following is a solution of the equation -5x + 2 = -13: answers: x=-9, x=75 x=3 x=-3
slamgirl [31]

Answer:

x= 3

Step-by-step explanation:

1. -5(3) + 2 = -13      

2. -15 + 2 = -13         <em>A positive times a negative will always equal a negative</em>

3. -13 = -13         <em>Whenever you add anything to a negative number, the                    </em>

<em>                            number becomes smaller   </em>

                     Ex:  -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, ...........

                           <em>Although the number itself becomes smaller, its value    </em>

<em>                             becomes bigger       </em>

Hope this helps.

7 0
3 years ago
I need a lot of help, please! ):
tankabanditka [31]

Answer:

I don't know sorry it even very hard and diffult for a high school kid

8 0
2 years ago
The school band is ordering health bars to sell for a fundraiser. The company that sells the bars charges $0.40 per bar plus $20
Pepsi [2]

Answer: They can order from 0 to 449 bars, but no more.

Step-by-step explanation:

Given: The school band is ordering health bars to sell for a fundraiser. The company that sells the bars charges $0.40 per bar plus $20.00 for shipping regardless of the size of the order. The band must spend less than $200.00 on bars for the fundraiser.

The inequality below relates x, the number of bars that could be ordered, with the shipping costs and their spending requirements.

0.40x+20

To solve for x,  subtract 20 on both sides, we get

0.40x

Divide 0.40 on both sides, we get

x......... → the number of  bars that could be ordered, with the shipping costs and their spending requirements must less than 450.

Thus, they can order from 0 to 449 bars, but no more.

4 0
3 years ago
Read 2 more answers
Jim had one hour to get to the
k0ka [10]
Jim has 27.5 minutes left to get to the airport.
7 0
3 years ago
PLEASE HELP ME WITH THIS
Alik [6]

Answer:

  • x + y ≤ 600
  • 5x +7y ≥ 3500
  • it is possible

Step-by-step explanation:

a) We can write two inequalities, one for the number of tickets, and one for the necessary revenue.

  x + y ≤ 600 . . . . . . . limit imposed by available seating

  5x +7y ≥ 3500 . . . . required revenue to meet expenses

__

b) For x = 330, the first inequality puts one limit on y:

  330 +y ≤ 600

  y ≤ 270

And the second inequality puts another limit on y:

  5(330) +7y ≥ 3500

  7y ≥ 1850 . . . . subtract 1650

  y ≥ 264.3 . . . . divide by 7

The number of tickets that must be sold to meet expenses is 265, which is less than the number that can be sold, 270. It is possible to meet expenses.

4 0
3 years ago
Other questions:
  • How do you find the surface area for this???
    14·1 answer
  • Can any one help me please
    13·1 answer
  • Which expression is equal to a•a•a•a•b•b
    11·2 answers
  • Write the standard form equation of the ellipse shown in the graph, and identify the foci.
    13·2 answers
  • -5[4-(-3)(2)] how to solve this
    6·2 answers
  • I need help with this please help????
    14·1 answer
  • The graph of the function f(x)=x^2-6x shifted 2 units to the left on the graph of g(x). Select the two functions that represent
    11·1 answer
  • Please i will give brainliest if right
    12·2 answers
  • STATE WHETHER THE WORKING SHOWN IN THE PICTURE BELOW IS TRUE OR FALSE.
    5·1 answer
  • How do I solve this?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!