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KonstantinChe [14]
3 years ago
10

How long does it take a car traveling at 50 mph to travel 75 miles? Use one of the following to find the answer.

Physics
2 answers:
Anna35 [415]3 years ago
5 0

Answer:

1.5 hours

Explanation:

Using the equation t=d/v to solve for time:

t=75 miles ÷ 50 miles per hour = 1.5 hours

alexira [117]3 years ago
3 0

Answer:

   1.25 miles/minute

Explanation:

i did the work on paper all of the ways worked but it taken me some time to finesh sorry if its wrong i tryed i hope i helped

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Can a goalkeeper at his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance will
zmey [24]

The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

Explanation:

Consider the vertical motion of ball,

We have equation of motion v = u + at

     Initial velocity, u  = u sin θ

     Final velocity, v =  0 m/s    

     Acceleration = -g

     Substituting

                      v = u + at  

                      0 = u sin θ - g t

                      t=\frac{usin\theta }{g}

This is the time of flight.

Consider the horizontal motion of ball,

        Initial velocity, u =  u cos θ

        Acceleration, a =0 m/s²  

        Time, t=\frac{usin\theta }{g}  

     Substituting

                      s = ut + 0.5 at²

                      s=ucos\theta \times \frac{usin\theta }{g}+0.5\times 0\times (\frac{usin\theta }{g})^2\\\\s=\frac{u^2sin\theta cos\theta}{g}\\\\s=\frac{u^2sin2\theta}{2g}

This is the range.

In this problem

              u = 30 m/s

              g = 9.81 m/s²

              θ = 45° - For maximum range

Substituting

               s=\frac{30^2\times sin(2\times 45)}{2\times 9.81}=45.87m

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.

So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

6 0
3 years ago
PLSSS HELP 100 POINTS AND BRAINLIEST!!1!1!1!1!1!11!11!1!1!!!!!
ANEK [815]

Answer:

A.model the reflection of a light wave

The Wave Model of Light Toolkit provides teachers with standards-based resources for designing lesson plans and units that pertain to such topics as the light's wavelike behaviors, wave-particle duality, light-wave interference, and light polarization

B. .model the absorption of a light wave

The simplest model is the Drude/Lorentz model, where the light wave makes charged particle oscillate while the particle is also being damped by a force of friction (damping force)

A mirror provides the foremost common model for reflective light wave reflection and generally consists of a glass sheet with a gold coating wherever the many reflections happen. Reflection is increased in metals by suppression of wave propagation on the far side their skin depths

C.model the transmimssion of a light wave

The Wave Model describes how light propagates in the same way as we model ocean waves moving through the water. By thinking of light as an oscillating wave, we can account for properties of light such as its wavelength and frequency. By including wavelength information, the Wave Model can be used to explain colors.

Explanation:

3 0
2 years ago
How does Piggy feel about being called "Piggy"?
denpristay [2]

Answer:

good because piggy loves peppa pig :3

Explanation:

4 0
3 years ago
If two charged objects in a laboratory are brought to a distance of 0.22 meters away from each other. What is
zysi [14]

Answer:

q_2=2.47\times 10^{-4}\ C

Explanation:

The charge on one object, q_1=9.9\times 10^{-5}\ C

The distance between the charges, r = 0.22 m

The force between the charges, F = 4,550 N

Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :

F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{4550\times (0.22) ^2}{9\times 10^9\times 9.9\times 10^{-5}}\\\\q_2=2.47\times 10^{-4}\ C

So, the charge on the other sphere is 2.47\times 10^{-4}\ C.

7 0
3 years ago
Which runner has greater kinetic energy: a 45 kg runner moving at a speed of 7 m per second or a 93 kg runner moving at a
bagirrra123 [75]

Kinetic Energy = (1/2) (mass) (speed)

First runner:  KE = (1/2) (45kg) (49 m/s)  =  1,102.5 Joules  

Second runner:  KE = (1/2) (93kg) (9 m/s)  =  418.5 Joules

The <em>first runner </em><em>has 163</em>% more kinetic energy than the second runner has.

7 0
3 years ago
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