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2 years ago

How long does it take to travel a distance of 672km at a speed of 95km/h?

Physics

1 answer:

Brilliant_brown [7]2 years ago

6 0

Answer:

7.07 hours

Explanation:

divide the distance by the speed

so in this case, divide 672 by 95

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Jobisdone [24]

$\text{Acceleration}=\frac{d^2}{dt^2}\text{displacement}$
So the dimensions of acceleration is $LT^{-2}$
Any answer that comes under that definition is correct.

6 0

3 years ago

Read 2 more answers

Would a ship in Lake Ontario (fresh water) float higher or lower in the water than in the Atlantic Ocean (salt water)?

ohaa [14]

Atlantic Ocean (salt water)

8 0

2 years ago

If the sun in 148 million kilometers from the earth, how many minutes will it take the light from the sun to reach the earth?

Natasha2012 [34]

Answer:

about 8 mins and 20 secs

Explanation:

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3 years ago

A 50.0 kg object is moving at 18.2 m/s when a 200 N force

gayaneshka [121]

Answer:

distance = 21.56 m

Explanation:

given data

mass = 50 kg

initial velocity = 18.2 m/s

force = -200 N ( here force applied to opposite direction )

final velocity = 12.6 m/s

solution

we know here acceleration will be as

acceleration a = force ÷ mass

a = $\frac{-200}{50}$ = -4 m/s²

we get here now required time that is

required time = $\frac{V_{(final)} - V_{(initial)}}{a}$ ...............1

put here value

required time = $\frac{12.6-18.2}{-4}$

so distance will be

distance = $\frac{V_{(final)}^2 - V_{(initial)}^2}{2a}$ ........2

distance = $\frac{12.6}^2 -{18.2}^2}{2\times (-4)}$

distance = 21.56 m

7 0

2 years ago

Mayan kings and many school sports teams are named for the puma, cougar, or mountain lion felis concolor, the best jumper among

denis23 [38]

To reach a vertical height of 13.8 ft against gravity, which has an acceleration of 32 ft/s^2, the required vertical speed can be calculated from the equation:
vi^2 - vf^2 = 2*g*h
Given that it has vf = 0 (it is not moving vertically at its maximum height), g = 32, and h = 13.8, we can solve for vi:
vi^2 = 29.72 ft/s
This is only its vertical speed, so this is equivalent to its original speed multiplied by the sine of the angle:
29.72 ft/s = (v_original)*(sin 42.2<span>°</span>)
v_original = 44.24 ft/s
Converting to m/s, this can be divided by 3.28 to get 13.49 m/s.

4 0

3 years ago