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solniwko [45]
3 years ago
14

You toss a ball straight up in the air. Immediately after you let go of it, what force or forces are acting on the ball

Physics
1 answer:
viva [34]3 years ago
8 0

Answer and Explanation: When tossing a ball up in the air, the forces acting on the ball are due to Gravity, which is defined by gravitational acceleration on that location on Earth (approximately 9.8 m/s²) multiplied by mass of the ball; Force of thrown, i.e., the force you threw the ball and air resistance force, which is proportional to the square of the ball's through the air and the ball's cross section area. To facilite calculations, air resistance force is normally ignored.

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A truck with 28-in.-diameter wheels is traveling at 50 mi/h. Find the angular speed of the wheels in rad/min, *hint convert mile
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Answer:

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Explanation:

Given data

d=28in\\r=d/2=28/2=14in\\v=50mi/hr

To find

Angular speed ω

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Solution

First we need to convert the speed of truck to inches per mile

as

1 mile=63360 inches

1 hour=60 minutes

so

v=(50*\frac{63360}{60} )\\v=52800in/min

Now to solve for angular speed ω by substituting the speed v and radius r in below equation

w=\frac{v}{r}\\ w=\frac{52800in/min}{14in}\\ w=3771.4rad/min

To solve for N(revolutions per minute) by substituting the angular speed ω in the following equation

N=\frac{w}{2\pi }\\ N=\frac{3771.4rad/min}{2\pi }\\ N=5921RPM  

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2 years ago
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