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2 years ago

What is a half-life in Chemistry?

Chemistry

1 answer:

makvit [3.9K]2 years ago

8 0

Answer:

half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive ...

Explanation:

braniest

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Answer the following questions for H2CrO4:

Sholpan [36]

If this molecule is one half of a buffer, then the formula of the second half of the buffer is M2CrO4 where M is a univalent metal.

<h3>What is a strong acid?</h3>

A weak acid is one that is able to ionize completely in solution. The acid called chromic acid H2CrO4 is not able to ionize completely in solution.

We know that a buffer is composed of a weak acid and its salt or a weak base and its salt hence if the acid H2CrO4 is present in a buffer then the other half must be salt of the acid.

If this molecule is one half of a buffer, then the formula of the second half of the buffer is M2CrO4 where M is a univalent metal.

Learn more about buffer:brainly.com/question/22821585

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7 0

2 years ago

Perform the following calculations and give your answer with the correct number of significant figures:

GarryVolchara [31]

I think this is the answer try it

172.3995<span>
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4 0

2 years ago

Read 2 more answers

Question 4

vazorg [7]

Answer:

H(aq) + NO3 (aq) + HF(aq)

Explanation:

In the given mixture of HNO3 (Nitric Acid) and HF (hydrofluoric acid) in water the major species present are H(aq) + NO3 (aq) + HF(aq).

On the reaction of HNO3 (Nitric Acid) and HF (hydrofluoric acid) in water , it will give a polar solution and will form a homogenous mixture.

Hence, the correct answer is "H(aq) + NO3 (aq) + HF(aq)".

4 0

2 years ago

1. A gas sample at a pressure of 5.00 atm has a volume of 3.00 L. If the gas pressure is changed to 760 mm Hg, what volume will

tatyana61 [14]

Answer:

V₂ = 15.00 atm

Explanation:

Given data:

Initial pressure = 5.00 atm

Initial volume = 3.00 L

Final pressure = 760 mmHg ( 760/760 = 1 atm)

Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 5.00 atm × 3.00 L / 1 atm

V₂ = 15.00 atm

8 0

3 years ago

When solving an equation using Gay-Lussac's law, which of the following steps do not apply? A. List your knowns and unknowns. B.

suter [353]

Answer:

C. Plug the unknowns into the ideal gas law formula.

Explanation:

Gay-Lussac's law states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically, it can be written as:

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where

p1 is the initial pressure

T1 is the initial temperature (in Kelvin)

p2 is the final pressure

T2 is the final temperature (in Kelvin)

Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:

A. List your knowns and unknowns.

B. Convert temperature to kelvin.

D. Solve for the unknown.

While the following step is not needed:

C. Plug the unknowns into the ideal gas law formula.

Because we do not need to use the ideal gas law formula.

8 0

3 years ago